I have no idea how to do this 😬😬 I tried but it never works. "The program you are given takes length and width of a rectangle as input. Complete the method to take t
Given N rectangles with edges parallel to axis, calculate the area of the union of all rectangles. The input and output are files specified in program arguments. Input is represented by N lines with 4 numbers separated by spaces, defining 2 opposite vertices of the rectangle. Output file shoul...
publicclassExercise13{publicstaticvoidmain(String[]strings){// Define constants for the width and height of the rectanglefinaldoublewidth=5.6;finaldoubleheight=8.5;// Calculate the perimeter of the rectangledoubleperimeter=2*(height+width);// Calculate the area of the rectangledoublearea=width*height...
System.out.printf("The area of Circle is %.2f, The perimeter of Circle is %.2f\n",circle.getArea(),circle.getPerimeter()); Rectangle rectangle = new Rectangle(4,6); System.out.printf("The area of Rectangle is %.2f, The perimeter of Circle is %.2f\n",rectangle.getArea(),rectangle...
Rectanglerectangle=(Rectangle)shape;// 将图形对象转换为矩形对象doublearea=rectangle.getWidth()*rectangle.getHeight();// 计算面积returnarea;// 返回面积值 1. 2. 3. 步骤4:实现圆面积的计算逻辑 为了计算圆的面积,我们需要将传入的图形对象转换为圆对象,并使用圆的半径来进行计算。下面是一个示例代码: ...
方法是您在 Java 程序中调用的代码单元。方法可以支持参数并且通常返回一个值。要在 Java 中创建方法,请遵循以下四个步骤。 1.打开您的文本编辑器并创建一个新文件。键入以下 Java 语句: 您编写的方法名为computeAreaOfRectangle. 它接受两个整数参数并返回一个整数,即两个参数的乘积。
Each rectangle is defined by its bottom left corner and top right corner as shown in the figure. Assume that the total area is never beyond the maximum possible value of int. 解题思路: 几何题目。 代码如下: 1 2 3 4 5 6 7 8
{@Overridepublicvoidvisit(Circlecircle){doublearea=Math.PI\*circle.getRadius()\*circle.getRadius();System.out.println("Area of Circle: "+area);}@Overridepublicvoidvisit(Rectanglerectangle){doublearea=rectangle.getWidth()\*rectangle.getHeight();System.out.println("Area of Rectangle: "+area);}...
The area of the rectangle is 84.0 The perimeter of the rectangle is 38.0 The area of the rectangle is now 72.0 The perimeter of the rectangle is now 36.0 Flowchart: For more Practice: Solve these Related Problems: Write a Java program to modify the "Rectangle" class to check if one recta...
// Double.toString(area)}public String getlength() {p = 3.14 * sideA;return String.valueOf(...