publicclassEightCharTo64BitTest{@TestpublicvoidtestConvertTo64Bit(){// Test case 1: "abcdefgh"Stringinput1="abcdefgh";longexpected1=25214903917L;assertEquals(expected1,EightCharTo64Bit.convertTo64Bit(input1));// Test case 2: "12345678"Stringinput2="12345678";longexpected2=79164837192L;assertE...
importjava.util.UUID;publicclassUUIDUtil{publicstaticStringgenerate64BitUUID(){// 生成一个UUIDUUIDuuid=UUID.randomUUID();// 获取UUID的高64位longhighBits=uuid.getMostSignificantBits();// 将高64位转换为16进制字符串returnLong.toHexString(highBits);}publicstaticvoidmain(String[]args){// 生成并打印64...
10bit、12bit,总计32bit*/privatestaticfinalintA_BITS=10;privatestaticfinalintB_BITS=10;privatestaticfinalintC_BITS=12;/*** A左移10+12* B左移12* C无
Cette procédure permet d'installer l'environnement JRE pour les plates-formes Linux 64 bits à l'aide d'un fichier binaire d'archive (.tar.gz). Accédez au site Web http://java.com, puis cliquez sur le bouton detéléchargement.
但是上面的bits只有16位,因为一个base64是6bits,所以可以用3个base64来表示,因为原始的bits少了两位,所以用0来补全: 0100110101100001+00 = 010011010110000100。 010011010110000100转换成为base64就是TWE,因为base64编码需要4个字符,所以最后的字符用=来补全,也就是说me经过base64之后变成TWE=。
BitSets are packed into arrays of "words." Currently a word is a long, which consists of 64 bits, requiring 6 address bits.The choice of word size is determined purely by performance concerns. 简言之: BitSet的数据封装到一个叫words的数组中,数组中的每一个word都是一个long类型的数据(我的理...
Cette procédure permet d'installer l'environnement JRE pour les plates-formes Linux RPM 64 bits, telles que Red Hat et SuSE, à l'aide d'un fichier binaire RPM (.rpm) situé dans l'emplacement système. Seul un utilisateur root peut procéder à cette installation. Accéde...
a single write to a non-volatile long or double value is treated astwo separate writes: one to each 32-bit half. This can result in a situation where a thread sees the first 32 bits of a 64-bit value from one write, and the second 32 bits from another write. Writes and reads of...
2. How 64-bit architecture is different? While 32 bits of information can only access 4 GB of RAM, a64-bit machine can access 17.2 BILLION GB of system memory, at least theoretically. So it must remove all the barriers of memory consumption from your system, right? But it does not. ...
32位JVM标记位布局:Address:0x1000|Offset|Size|Description|Values||:--:|:--:|:--:|:--:||0x0|8bits|Mark Word|1bit:biased lock;2bits:lock state;5bits:heap word index|64位JVM标记位布局:Address:0x1000|Offset|Size|Description|Values||:--:|:--:|:--:|:--:||0x0|16bits|Mark Word|...