这段代码会将currentTime对象按照指定格式转换为字符串,并保存在formattedTime中。 步骤3:使用Calendar类将时间加上12小时 最后,我们需要使用Calendar类来将当前时间加上12小时。代码如下: importjava.util.Calendar;Calendarcalendar=Calendar.getInstance();calendar.set
publicclassTimeFormatter24Hour{publicstaticvoidmain(String[]args){LocalTimenow=LocalTime.now();DateTimeFormatterformatter24Hour=DateTimeFormatter.ofPattern("HH:mm");StringformattedTime24=now.format(formatter24Hour);System.out.println("当前时间(24小时制):"+formattedTime24);}} 1. 2. 3. 4. 5. 6. ...
Try again:Enter time in 24-hour notation:16:05That is the same as4:05 PMAgain?(y/n)End of program要定义一个名为TimeFormatException的异常类.如果用户输入了不合法的时间,比如10:65,甚至是无意义的东西,比如8&*68,程序将会抛出、捕获并处理一个TimeFormatException ...
1. Patterns to Display Hours For formatting purposes, hour part of the time is represented in two ways: ‘hh’– hours in 12 hour format ‘HH’– hours in 24 hour format ‘a’– display the AM/PM information. Using the above information, we can create the following pattern to display ...
实现思路就是输入一个时间，之后会输出相应的12小时和24小时效果展示：import java.text.SimpleDateFormat;import java.util.Locale;import java.util.Scanner;public class App { public static void main(String[] args) { while (true) { System.out.println("Enter time in 24-hour notation:");...
In this tutorial, we’ll explore how to convert the 12-hour time format to the 24-hour time format using theDate Time APIand the legacyDate API. 2. Using the Date Time API TheDate Time APIintroduced in Java 8 provides a class to format time using different patterns. The 12-hour time...
In this tutorial we will see how to convert 12 hour format to 24 hour format and 24 hour format to 12 hour format in Java. Java - Convert 12 Hour data time format to 24 hour date time format We can change the pattern in the SimpleDateFormat for the conve
}public static void outTime(String line) throws TimeFormatException {SimpleDateFormat _24time = new SimpleDateFormat("HH:mm");SimpleDateFormat _12time = new SimpleDateFormat("hh:mm a",Locale.ENGLISH);try {String[] array = line.split(":");if (Integer.parseInt(array[0]) < ...
String dateString=formatter.format(currentTime); returndateString; } /** * 将长时间格式字符串转换为时间 yyyy-MM-dd HH:mm:ss * *@paramstrDate *@return */ publicstaticDate strToDateLong(String strDate) { SimpleDateFormat formatter=newSimpleDateFormat("yyyy-MM-dd HH:mm:ss"); ...
Try again:Enter time in 24-hour notation:16:05That is the same as4:05 PMAgain?(y/n)nEnd of program要定义一个名为TimeFormatException的异常类.如果用户输入了不合法的时间,比如10:65,甚至是无意义的东西,比如8&*68,程序将会抛出、捕获并处理一个TimeFormatException 扫码下载作业帮搜索答疑一搜即得...