一,用DOM4J 针对无重复标签的xml字符串格式,如下: 针对此种情况可用DOM4J解析法,引入 dom4j的相关jar包代码如下: Document document=DocumentHelper.parseText(xmlStr);//xmlStr为上图格式的字符串 Node VideoCompany=document.selectSingleNode("//VideoCompany");//获取节点对象,注意引号内的“//”必须加 ,否则报错 ...
//Element.asXML方法,获得包括该标签的所有XML数据 System.out.println(root.element("body").asXML()); } catch (Exception e) { e.printStackTrace(); } } } 总结: Document document=new SAXReader.reader(“xml文路径/文件名xxx.xml”);//得到Document对象 Element root = document.getRootElement()//...
</dependency> 比如阿里云视频转码服务的回调通知解析,代码如下: importorg.dom4j.Document;importorg.dom4j.DocumentException;importorg.dom4j.DocumentHelper;importorg.dom4j.Element;importjava.util.Iterator;publicclassDOMParser {publicstaticvoidmain(String[] args) { String strXML= "<?xml version=\"1.0\" enco...
import java.util.Iterator; public class DOMParser { public static void main(String[] args) { String strXML = "1692545896541241MyTopic1692545896541241bing-test3C39FB8C345BBFBA8-1-1687F6FAADD-200000015CAA1E9F5E9F854ACD8297B100BF8CCF9{\"jobId\":\"2384a4d89b1d4f1e869559e2ff8c9fad\",\"req...
import java.util.Iterator; public class DOMParser { public static void main(String[] args) { String strXML = "<?xml version=\"1.0\" encoding=\"UTF-8\"?> <Notification xmlns=\"http://mns.aliyuncs.com/doc/v1/\"> <TopicOwner>1692545896541241</TopicOwner> <TopicName>MyTopic</TopicName...
最简单的JAVA解析XML字符串方法 出处:https://www.cnblogs.com/acm-bingzi/p/java_dom4j.html 引入dom4j 包 <dependency> <groupId>dom4j</groupId> <artifactId>dom4j</artifactId> <version>1.6.1</version> </dependency> 比如阿里云视频转码服务的回调通知解析,代码如下:...