LeetCode: Is Subsequence键盘:MacBookPro, 视频播放量 117、弹幕量 0、点赞数 0、投硬币枚数 0、收藏人数 0、转发人数 0, 视频作者 Castor_ye, 作者简介 夜太美!撕心又裂肺!,相关视频:分享一个实用的刷leetcode的思路,5分钟讲透C++const,这么漂亮的程序界面,面试官
A subsequence of a string is a new string which is formed from the original string by deleting some (can be none) of the characters without disturbing the relative positions of the remaining characters. (ie, "ace" is a subsequence of "abcde" while "aec" is not). Example 1: s = "abc...
importcollectionsclassSolution(object):defisSubsequence(self,s,t):""":type s: str:type t: str:rtype: bool"""defbinary_search(nums,x):low,high=0,len(nums)whilelow<high:mid=(low+high)//2ifnums[mid]<x:low=mid+1else:high=midreturnhighifnotsandnott:returnTrueelifnotsandt:returnTrueeli...
英文网址:392. Is Subsequence。 中文网址:392. 判断子序列。 思路分析 求解关键:这道题的解法其实蕴含了贪心算法的思想。 参考解答 参考解答1: public class Solution { public boolean isSubsequence(String s, String t) { int slen = s.length(); int tlen = t.length(); int sl = 0; int tl = ...
【Leetcode】Is Subsequence https://leetcode.com/contest/3/problems/is-subsequence/ 题目: s and a string t, check if s is subsequence of t. s and t. t is potentially a very long (length ~= 500,000) string, and s "ace"is a subsequence of"abcde"while"aec"Example 1:...
Leetcode - Is Subsequence publicclassSolution{publicbooleanisSubsequence(Strings,Stringt){if(s==null||t==null){returnfalse;}elseif(t.length()<s.length()){returnfalse;}intpre=0;for(inti=0;i<s.length();i++){charcurr=s.charAt(i);intindex=t.indexOf(""+curr,pre);if(index==-1){...
链接:https://leetcode-cn.com/problems/is-subsequence 著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。 思路 依次检查 s 中的每个字符是否出现在 t 中,并且要求 s 中后面的字符的在 t 中出现的位置对应递增。 当有很多个 s ,只有一 t 个时,可以考虑用字典对 t 建立索引。键为 t...
# @author:leacoder # @des: 双指针解法 判断子序列 class Solution: def isSubsequence(self, s: str, t: str) -> bool: # 判断 s 是否为 t 的子序列。 # 指针 point_s 指向 s 第一个字符,指针 point_t 指向 t 第一个字符。逐一判断 point_s 所指向的字符是否在 t 中存在。 point_s = 0...
392. Is Subsequence # 题目 # Given a string s and a string t, check if s is subsequence of t. You may assume that there is only lower case English letters in both s and t. t is potentially a very long (length ~= 500,000) string, and s is a short string
classSolution {public:boolisSubsequence(strings,stringt) {if(s.empty())returntrue;inti =0, j =0;while(i < s.size() && j <t.size()) {if(s[i] == t[j]) ++i;++j; }returni ==s.size(); } }; 本文转自博客园Grandyang的博客,原文链接:是子序列[LeetCode] Is Subsequence,如需转...