A subsequence of a string is a new string which is formed from the original string by deleting some (can be none) of the characters without disturbing the relative positions of the remaining characters. (ie, "ace" is a subsequence of "abcde" while "aec" is not). Example 1: s = "abc...
importcollectionsclassSolution(object):defisSubsequence(self,s,t):""":type s: str:type t: str:rtype: bool"""defbinary_search(nums,x):low,high=0,len(nums)whilelow<high:mid=(low+high)//2ifnums[mid]<x:low=mid+1else:high=midreturnhighifnotsandnott:returnTrueelifnotsandt:returnTrueeli...
英文网址:392. Is Subsequence。 中文网址:392. 判断子序列。 思路分析 求解关键:这道题的解法其实蕴含了贪心算法的思想。 参考解答 参考解答1: public class Solution { public boolean isSubsequence(String s, String t) { int slen = s.length(); int tlen = t.length(); int sl = 0; int tl = ...
Can you solve this real interview question? Is Subsequence - Given two strings s and t, return true if s is a subsequence of t, or false otherwise. A subsequence of a string is a new string that is formed from the original string by deleting some (can b
LeetCode 392. Is Subsequence 简介:给定字符串 s 和 t ,判断 s 是否为 t 的子序列。你可以认为 s 和 t 中仅包含英文小写字母。字符串 t 可能会很长(长度 ~= 500,000),而 s 是个短字符串(长度 <=100)。字符串的一个子序列是原始字符串删除一些(也可以不删除)字符而不改变剩余字符相对位置形成的新...
LeetCode 392. Is Subsequence 程序员木子 香港浸会大学 数据分析与人工智能硕士在读 来自专栏 · LeetCode Description Given a string s and a string t, check if s is subsequence of t. You may assume that there is only lower case English letters in both s and t. t is potentially a ...
题目描述: LeetCode 392. Is Subsequence Given a string s and a string t, check if s is subsequence of t. You may assume that there is only lower case English letters in both s and t. t is potentially a very long (length ~= 500,000) string, and s is a...
LeetCode 392. Is Subsequence 详解 题目详情 给定字符串s和t,判断s是否为t的子序列。 你可以认为s和t中仅包含英文小写字母。字符串t可能会很长(长度 ~= 500,000),而s是个短字符串(长度 <=100)。 字符串的一个子序列是原始字符串删除一些(也可以不删除)字符而不改变剩余字符相对位置形成的新字符串。(...
leet_code:链接 问题描述:判断序列a是否为序列b的子序列 输入输出样例: intput :a = “abc”, b = “ahbgdc” output: true(1). c++ 代码实现 class Solution { public: bool isSubsequence(string S1, string S2) { int idx = 0, end = S1.size(); for (char val : S2) { if (S1[idx]...
392. Is Subsequence # 题目 # Given a string s and a string t, check if s is subsequence of t. You may assume that there is only lower case English letters in both s and t. t is potentially a very long (length ~= 500,000) string, and s is a short string