123 //Given an integer, write a function to determine if it is a power of two.publicclassisPowerOfTwo {publicstaticbooleanisPowerOfTwo(intn) {if(n == 1)returntrue;elseif(n < 0)returnfalse;else{ String str=Integer.toBinaryString(n);for(inti=1;i<str.length();i++) {if('1'==str.charAt(i))returnfalse; } }returntrue; }publicstaticvoidmain(String[]...
class Solution: def isPowerOfTwo(self, n: int) -> bool: """ :type n: int :rtype: bool """ return n > 0 and n & n - 1 == 02 的幂的二进制形式最高位一定是1,其余为0 用常规思路也行 class Solution(object): def isPowerOfTwo(self, n): return n > 0 and 2**int(math....
如果是power of two, 则2进制表达中,有且仅有一个1. 可以通过移位来数1的个数, 这里用了一个巧妙的办法, 即判断 N & (N-1) 是否为0. [CODE] 来源:http://blog.csdn.net/xudli/article/details/46784163 publicclassSolution{publicbooleanIsPowerOfTwo(intn){returnn >0&& ((n & (n -1)) ==...
- Created using LeetHub v2 LeetCode Topics Array 0130-surrounded-regions 0721-accounts-merge 0854-making-a-large-island 1073-number-of-enclaves 1171-shortest-path-in-binary-matrix 2766-find-the-prefix-common-array-of-two-arrays Depth-First Search 0130-surrounded-regions 0207-course-schedule 0210-...
package leetcode // 解法一 O(n^2) func isSubsequence(s string, t string) bool { index := 0 for i := 0; i < len(s); i++ { flag := false for ; index < len(t); index++ { if s[i] == t[index] { flag = true break } } if flag == true { index++ continue } else...
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Posted by kittFiled inLeetCodeTagged byComments[0] Two Sum @ LeetCode (Python) 2014年1月29日 13:51 经Derek提醒,可用dict来存每个integer的初始位置。需注意num=[0,4,3,0], target=0这种两加数相等的情况。 继续阅读 Posted by kittFiled inLeetCodeTagged byComments[5] ...
leetcode 697[easy]---Degree of an Array 难度:easy Given a non-empty array of non-negative integers nums, the degree of this array is defined as the maximum frequency of any one of its elements. Your task is to find the smallest......