Thereby, globally at any given time, it is possible to contemplate the complex random phase field contribution as a holomorphic integration of a complex rough noise: $$\begin{aligned} \delta \phi \left( x_0, x(t)\right) = i\int _{x_0}^{x(t)} \text{ d }\mathcal {B}^0(s)...
Huang, X., Ji, S., Yau, S.S.T.: An example of a real analytic strongly pseudoconvex hypersurface which is not holomorphically equivalent to any algebraic hypersurface. Ark. Mat. 39(1), 75-93 (2001)An example of a real analytic strongly pseudoconvex hypersurface which is not holomorphic...
How to prove that function is holomorphic? Show how to find stable and unstable manifolds. Let r = <x, y, z >, r = || r || and f a scalar function . Prove that nabla 2 f (r) = f "(r) + 1 / r f '(r). Why is the stable manifold connected?
Suppose that {eq}f(z) {/eq} is a holomorphic function. If {eq}z {/eq} is in the domain of {eq}f {/eq}, let {eq}D {/eq} be a closed disk centered at {eq}z {/eq} which is contained in the domain of {eq}f {/eq}, and let {eq}\Gamma {/eq} be ...
An example of real analytic strongly pseudoconvex hypersurface which is not holomorphically equivalent to any algebraic hypersurfaces, Ark - Huang, Ji, et al. () Citation Context ...o the germ of an algebraic hypersurface, but for each p ∈ E, (M, p) cannot be holomorphically equivalent ...