在LeetCode上我写了两种解法,一种就是按照定义递归的把条件写出来再判断(直接法),另一种就是利用BST的性质:中序遍历结果为升序(性质法),注意空树是符合BST定义的。 首先是直接法,其实就是定义的代码翻译: (1)节点的左子树只包含小于当前节点的数。 (2)节点的右子树只包含大于当前节点的数。 (3)所有左子树和右子树自身必须也是
* Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode() : val(0), left(nullptr), right(nullptr) {} * TreeNode(int x) : val(x), left(nullptr), right(nullptr) {} * TreeNode(int x, TreeNode *left, TreeNode ...
[Leetcode] Binary tree--653. Two Sum IV - Input is a BST Given a Binary Search Tree and a target number, return true if there exist two elements in the BST such that their sum is equal to the given target. Example 1: Input: 5 / \ 3 6 / \ \ 2 4 7 Target = 9 Output: Tr...
Binary Search Tree 0789-kth-largest-element-in-a-stream Heap (Priority Queue) 0239-sliding-window-maximum 0407-trapping-rain-water-ii 0744-network-delay-time 0778-reorganize-string 0789-kth-largest-element-in-a-stream 1304-longest-happy-string 1325-path-with-maximum-probability 1485-minimum-cost-...
This repository contains my solutions to LeetCode problems. Created with ️ by LeetPush Made by Tut: GitHub - LinkedIn Hüsam: GitHub - LinkedIn Happy coding! 🚀 LeetCode Topics Tree 0102-binary-tree-level-order-traversal 0104-maximum-depth-of-binary-tree 0106-construct-binary-tree-from...
AHeapis a specialized tree based structure data structure that satisfies theheapproperty: if A is a parent node of B, then the key (the value) of node A is ordered with respect to the key of node B with the same ordering applying across the entire heap. A heap can be classified furth...
◌ Detailed Theoretical analysis cmu.edu ◌ Binary search khanacademy.orgPractice Problems: Searching ◌ Searching Algorithms geeksforgeeks.org ◌ GFG: Binary Search geeksforgeeks.org ◌ Leetcode: Interview Practice Leetcode: Practice Binary-SearchBack...
This repository is managed by LeetPush extension: https://github.com/husamahmud/LeetPush - deepu144/Leetcode
BinaryTree.cpp性质非空二叉树第 i 层最多 2(i-1) 个结点 (i >= 1) 深度为 k 的二叉树最多 2k - 1 个结点 (k >= 1) 度为0 的结点数为 n0,度为 2 的结点数为 n2,则 n0 = n2 + 1 有n 个结点的完全二叉树深度 k = ⌊ log2(n) ⌋ + 1 对于含 n 个结点的完全二叉树中编号为...
- Created using LeetHub v2 LeetCode Topics Array 0130-surrounded-regions 0721-accounts-merge 0854-making-a-large-island 1073-number-of-enclaves 1171-shortest-path-in-binary-matrix 2766-find-the-prefix-common-array-of-two-arrays Depth-First Search 0130-surrounded-regions 0207-course-schedule 0210-...