Function: A function is a relation where everyx-value is unique. So, the relation(1,3),(2,5),(3,11)is a function as nox-value is repeated. Meanwhile, the relationy=±xis not a function it contains the points(1,1
这种关系是一个函数?which relation is a function?A:(0,1),(0,2),(2,3),(3,2)}B:{(2,4),(3,5),(4,6),(5,6)}C:{(3,1),(1,3),(2,1),(2,3)}D:{(5,2),(5,3),(2,2),(3.3)}1.We are thinking about the x and y values in a coordinate grid.2.Another ...
( (-1,1)) , ( (0,0)) , ( (1,-1)) 相关知识点: 试题来源: 解析 Since there is one value of ( y) for every value of ( x) in ( (-1,1),(0,0),(1,-1)), this relation is a function. The relation is a function.反馈 收藏 ...
It is a relationship, but it is not a function, for these reasons: Value "3" in X has no relation in Y Value "4" in X has no relation in Y Value "5" is related to more than one value in Y (But the fact that "6" in Y has no relationship does not matter)Vertical...
Is the following relation a function? {eq}\{(1, -2), (1, -3), (2, 1), (3, -2) \} {/eq} Function: y=f(x) is said to be a function if for every every output of y has a distinct input of x. In other words, f is a function if {eq}a= b\text{, then ...
A function is a relation where each x is paired with no more than one y. Note that the same y can be paired with different x's, but not the reverse. All linear equations, with the exception of vertical and horizontal lines, are functions. Is {(2,3),(4,1),(0,1),(2,−2),...
Which relation is a function? ( ) A. \( (1,1),(2,2),(3,3),(4,4),(5,5)\) B. \( (1,1),(1,2),(1,3),(1,7),(1,9)\) C. \( (1,4),(3,4),(3,4),(4,4),(5,4)\) D. \( (1,1),(2,2),(1,3),(2,4),(5,5)\) 相关知识点: ...
3. The above relation is a function. It is a one-to-one relation. 相关知识点: 试题来源: 解析 (a) A function. Many-to-one relation.(b) Not a function. The element 1 ismapped onto two elements.mapped onto two elements. 反馈 收藏 ...
Determine whether the relation is a function. {eq}\left \{ (-5, -4), (-2, 9), (-1, -2),(-1, 7) \right \} {/eq} Relations and Functions: A function can be imagined as a box that transforms an input to some output. Given some input {eq}k {/eq}, to this ...
Is the inverse of relations t a function? Relation t {eq}\begin{array}{|l|l|l|l|l|l|l|} \hline x & 0 &1 &2 & 3 \\ \hline y & -2 & 1 & 10 & 2\\ \hline \end{array} {/eq} Function and ...