( ) A. $-4$ B. $-2$ C. $1$ D. $4$ 答案 D相关推荐 1$f$ is a continuous, differentiable function represented in this table. Given $g(x)=f(x^{2})$, find $g'(2)$. ( ) A. $-4$ B. $-2$ C. $1$ D. $4$ 反馈 收藏
Prove the following theorem. Theorem: Let u be a differentiable function of x, and let f be a continuous function of u. Then \int f (u(x)) \cdot \frac{du}{dx} = \int f(u) du + C where C is an arbit How to prove a function is infinitely differentiable?
If f is a continuous function on [0,1], differentiable in (0, 1) such that f(1)=0, then there exists some c in (0,1) such that cf^(prime)(c)-f(c)=0 cf^(pri
17. If a function f(x) is differentiable at x =c, prove that it is continuous at x = c. 相关知识点: 试题来源: 解析Since fis differentiable atc. we have i lim_(x→c)(f(x)-f(c))/(x-c)=f'(c) But for, we have x≠qc f(x)-f(x)=(f(x)-f(c))/(x-c)⋅(x-c...
Let h(x) = x ^(2) and g(x) = cos x h (x) = x^(2) is a polynimial function which is continuous for all real value of x and g(x) = cos x is continuous for all real value of x. Now (goh ) (x) = g[ h(x)] =g (x^(2)) = cos x ^(2) :' g(x) and h(...
A function f(x) is differentiable in and f' is continuous in .Use Fundamental Theorem of Calculus to evaluate:a) f'b) f' 答案 a) b) 相关推荐 1A function f(x) is differentiable in and f' is continuous in .Use Fundamental Theorem of Calculus to evaluate:a) f'b) f' 反馈 收藏 ...
A differentiable function is a continuous function, however a function can be continuous at a point and at this point not be differentiable, in the latter case the function has a peak at this point. Answer and Explanation: Analyze the data that they give us in ...
FunctionDerivativeThe article discusses an example of a mathematical function between ordered sets that saves the given order monotonic function which can be differentiated anywhere and the derivative of this function is not continuous. It describes the definition of the differential function with detailed...
【题目】 A function f(x) is differentiable in (-∞,∞) and f' is continuous in (-∞,∞).Use Fundamental T heorem o f Calculus to eva luate:a$$ \frac { 1 d } { 1 a x } $$)$$ ( \int _ { x } ^ { x ^ { 2 } } f ( t ) , t $$)b)$$ \int _ { x } ...
From here we have that if a function isn't continuous it is differentiable. Answer and Explanation:1 (a): Since we have: limx→2−f(x)=0,limx→2+f(x)=−2 And because:0≠−2we conclude that the... Learn more abo...