To determine which of the given numbers is divisible by 9, we can use the rule that states a number is divisible by 9 if the sum of its digits is divisible by 9. Let's analyze each option step by step.1. Identify the Numbers: L
Write the contrapositive of :if a number is divisible by 9 then it is divisible by 3" View Solution Is 989 divisible by 9? View Solution A number is divisible by 6 and 8. Is it also divisible by6×8=48? Justify your answer with the help of an example ...
From1thru9,the sum is45,10 thru19,the sum is55,20 thru29is65,and30thru39is75.Thus the sum of the digits is45+55+65+75+4+5+6+7+8=240+30=270,and thus N is divisible by9. Now.refer to the above solution N=4(mod5)andN=0(mod9)From this information,we can conclude this i...
百度试题 结果1 题目Q5. What is the sum of all numbers between 100 and 200, which is divisible by 9? B A. 1863 B. 1683 C. 1386 D. 1638 相关知识点: 试题来源: 解析 B 反馈 收藏
Answer to: Prove that the sum of cubes of any three consecutive natural numbers is divisible by 9. By signing up, you'll get thousands of...
Divisibility tests and rules explained, defined and with examples for divisibility by 2,3,4,5,6,8,9,10, and 11.Divisibility Calculator
GMAT 考满分题库一个正整数如果要被9整除，那么这个正整数每一个digit相加要可以被9整除（例如判断1233能不能被9整除，只要看1+2+3+3=9是不是能被9整除，只要后者能被9整除，那么1233也能被9整除），这道题是要判断25×10n+k×102n能不能被9整除，10的N次方和10的2N次方无论N是多少，digit相加都为0。
①It is divisible by 7 ;②When divisible by 8, it has a remainder of 1;③When divisible by 9, it has a remainder of 2。The 3-digit number with the above properties is 。 相关知识点: 试题来源: 解析 497 题目要求找出一个三位数同时满足三个条件:①能被7整除;②除以8余1;③除以9余2。
If a whole number is divisible by 111, then it must be divisible by ( ). A: 5 B: 7 C: 11 D: 37 相关知识点: 试题来源: 解析 DOf the following choices, only 37 is a factor of 111.如果一个整数能被111整除,那么它一定能被( ) 整除.A.5B.7C.11D.37在下列选项中,只有37是111的...
Adj. 1. even - divisible by two odd, uneven - not divisible by two 2. even - equal in degree or extent or amount; or equally matched or balanced; "even amounts of butter and sugar"; "on even terms"; "it was a fifty-fifty (or even) split"; "had a fifty-fifty (or even) ch...