例如判断1233能不能被9整除，只要看1+2+3+3=9是不是能被9整除，只要后者能被9整除，那么1233也能被9整除），这道题是要判断25×10n+k×102n能不能被9整除，10的N次方和10的2N次方无论N是多少，digit相加都为0。其实只要判断2+5+k等于多少的时候可以被9整除，这样来看只有2+5+47=54能够被9整除。按...
解析 能被5和7除尽的必定能被35除尽,但不一定能被70除尽,要能被70除尽,需要同时能被5,7,2除尽 结果一 题目 divisible到底是能被除尽还是整除的意思 题目是这样的说n is divisible by both 5and 7 then n must also be divisible by 但是我觉得要是说是像字典里一样解释为除尽的话 那不是应该也能...
divisible到底是能被除尽还是整除的意思题目是这样的说n is divisible by both 5and 7 then n must also be divisible by 但是我觉得要是说是像字典里一样解释为除尽的话 那不是应该也能被70除尽么? 答案 能被5和7除尽的必定能被35除尽,但不一定能被70除尽,要能被70除尽,需要同时能被5,7,2除尽相...
则最小公倍数为2⁶*3² = 576,最大公约数为2³= 9 👉商和余数 Quotient and Remainder 【难点警告⚠】 ✅10÷3 = 3 ……1 ✅-10÷3 = -4 ……2 ✅10÷12 = 0 ……10 ❌10÷3 = 2 ……4【余数不能大于除数】 Be divide...
Divisibility tests and rules explained, defined and with examples for divisibility by 2,3,4,5,6,8,9,10, and 11.Divisibility Calculator
to unlocking the mystery of life itself. As such, everyone at some point needs to learn how to easily divide numbers. All you need is a basic understanding of simple addition. Here is an incredibly easy way to tell if any integer is divisible by 9, using the number 189 as an example....
百度试题 结果1 题目 891÷3=297. Since 297=27×11, 297 is divisible by 27( ). A. 7 B. 17 C. 27 D. 97 相关知识点: 试题来源: 解析 C 反馈 收藏
Since the greatest common factor of 12 and 20 is 4, the least common multiple is 12 * 20 ÷ 4 = 60. (Notice that 60 is 12 * 5 and also 20* 3.) Notice that the only integer among the choices that is a factor of 60 is (A) 15....
例2:If n is a positive integer and the product of all the integers from 1 to n, inclusive, is divisible by 990, what is the least possible value of n ? A. 8 B. 9 C. 10 D. 11 E. 12 【解析】D 990=2*3^2*5*11 n要能够被11整除 ...
gmat数学题.if n is a positive integer and n^2 is divisible by 72,then the largest positive integer that must divide n is 答案是24, 扫码下载作业帮搜索答疑一搜即得 答案解析 查看更多优质解析 解答一 举报 72=8*9=2*2*2*3*3若72a=2*2*2*3*3a=n^2所以n最小为2*2*3=12,a=2. 解析看...