解析 The birds can be matched in pairs. The number of birds is even.You can check your answer by counting the birds. There are 10 birds.10 is an even number.An even number of objects can be matched in pairs. An odd number ofobjects cannot be matched in pairs. ...
百度试题 结果1 题目7 is an odd number.is an even number.Which one of the following gives an odd number?(1)+※+2(2)①+①++2(3) ×※× 2(4) ※×※×2 相关知识点: 试题来源: 解析 1 反馈 收藏
Check whether a number is even or odd.Steven L. Scott
# Python program to check if the input number is odd or even. # A number is even if division by 2 gives a remainder of 0. # If the remainder is 1, it is an odd number. num = int(input("Enter a number: ")) if (num % 2) == 0: print("{0} is Even".format(num)) else...
解析 根据常识, 我们知道13是一个奇数, "odd"表示奇数, 奇数的, 而"even"表示偶数, 偶数的. 所以这里用"odd".故答案为: odd结果一 题目 13 is an (odd,even) number. 答案 根据常识, 我们知道13是一个奇数, "odd"表示奇数, 奇数的, 而"even"表示偶数, 偶数的. 所以这里用"odd".故答案为: odd...
百度试题 结果1 题目Is 5 even or odd?even odd 相关知识点: 试题来源: 解析 Anumberisevenifitendsin2,4,6,8,or0.Anumberisoddifitendsin1,3,5,7,or9.5 is odd. 反馈 收藏
The most common approach to check if a number is even or odd in Python is using themodulo operator (%). The modulo operator returns the remainder after division. An even number is evenly divisible by 2 with no remainder, while an odd number leaves a remainder of 1 when divided by 2. ...
Check give number is Even or Odd #include<iostream.h>#include<conio.h>voidmain(){intno;clrscr();cout<<"Enter any num: ";cin>>no;if(no%2==0){cout<<"Even num";}else{cout<<"Odd num";}getch();} Output Enter any num : 5 Odd num ...
The product of two consecutive odd integers is 1 less than four times their sum. Find the two integers. Given a whole number, how do you determine whether it is even or odd? Determine whether f is even, odd, or neither even nor odd. f (x) = 2 x^5 - 3 x^2 + 2 ...
【题目】 (a) m is an odd number.Which of the numbers below mustbe even, and which must be odd?Write 'odd' or 'even' undereach one.2m m23m-1(m-1)(m+1)(b) m is an odd number.Is the number odd, or even, oris it not possible to tel l?T ick () thecorrect bor.odd ...