Letn=1,then6^n-1=5whichisdivisibl e by 5 So true for n = 1 Assume true for n = k and let n =k+ 1 6^(k+1)-1=6(6^k)-1 =5(6^k)+6^k-1 =5(6^k)+5Af( or some integer A since 6*-1 is divisible by 5 =5(6^k+A) So divisible by 5 True for n = 1 and...
题目Is 41,815 divisible by 6?A:yesB:no 相关知识点: 试题来源: 解析 B None 反馈 收藏
Is the integer p divisible by 5 ? p is divisible by 10. p is not divisible by 15. 选项: A、Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient. B、Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient. C、BOTH statements TOGETHE...
翻译结果5复制译文编辑译文朗读译文返回顶部 然后n由3是可分的,如果和,只有当总和的它 相关内容 a南海 South China Sea[translate] aThat's all for today. 那是全部为今天。[translate] a他叫吴鹏他是中国人 His name is Wu the huge mythical bird he is the Chinese[translate] ...
Which of the following options is completely divisible by 11 निम्नलिखित में से कौन सा विकल्प 11 से पूर्णतः विभाजित है ?
divisible到底是能被除尽还是整除的意思题目是这样的说n is divisible by both 5and 7 then n must also be divisible by 但是我觉得要是说是像字典里一样解释为除尽的话 那不是应该也能被70除尽么? 答案 能被5和7除尽的必定能被35除尽,但不一定能被70除尽,要能被70除尽,需要同时能被5,7,2除尽相...
结果1 题目 10. The number 541g5072h6 is divisible by 72. If g and A each represent a single digit, how many pairs of values of g and h are possible? ( )(A)1(B)2(C)3(D)4 相关知识点: 试题来源: 解析 10.C 反馈 收藏 ...
gmat数学题.if n is a positive integer and n^2 is divisible by 72,then the largest positive integer that must divide n is 答案是24, 扫码下载作业帮搜索答疑一搜即得 答案解析 查看更多优质解析 解答一 举报 72=8*9=2*2*2*3*3若72a=2*2*2*3*3a=n^2所以n最小为2*2*3=12,a=2. 解析看...
证明:(1)当n=1时,(5n+24)6^n +1 =(5+24)*6+1=175 =25*7 ∴此时命题成立 (2)假设当n=k时命题成立(k≥1)即(5k+24)*6^k+1能被25整除 那么当n=k+1时 [5(k+1)+24]*6^(k+1)+1 =[(5k+24)+5](6*6^k)+1 =6*(5k+24)*6^k+30*6^k+1 =6[(5k+24)*6^...
Divisibility tests and rules explained, defined and with examples for divisibility by 2,3,4,5,6,8,9,10, and 11.Divisibility Calculator