试题来源: 解析 D Of the following choices, only 37 is a factor of 111.如果一个整数能被111整除,那么它一定能被( ) 整除.\text{A}.5 \text{B}.7 \text{C}.11 \text{D}.37在下列选项中,只有37是111的因数.故选\text{D}.反馈 收藏 ...
(1) Is 9184 divisible by 2? If not, what is the remainder? (2) Is 3725 divisible by 5? If not, what is the remainder? (3) Is 8245 divisible by 25? If not, what is the remainder? 相关知识点: 试题来源: 解析 (1) Yes (2) Yes (3) No. r20反馈...
那么这个正整数每一个digit相加要可以被9整除（例如判断1233能不能被9整除，只要看1+2+3+3=9是不是...
C. 6D. 9相关知识点: 试题来源: 解析 C Try 1+2+3+4+5+6+7+8+9=45; it's not divisible by 6. 9个连续整数的和不是总能被( )整除. A.1 B.3 C.6 D.9 尝试1+2+3+4+5+6+7+8+9=45,不可以被6整除. 故选C.反馈 收藏 ...
英语翻译请翻译这段话:f x is divisible by y,then every prime factor in y must be found in x.Example:If 504 is divisible by y,then y could be 168 (2^3 * 3 * 7),or 21 (3 * 7),or 4(2^2),or many other things.Y could not,however,be equal to 10
百度试题 结果1 题目If the number 117B49 is completely divisible by 7, then the smallest natural number in place of B will be: D A) 2B)5C)7D) 6E)None of these 相关知识点: 试题来源: 解析 D 反馈 收藏
百度试题 结果1 题目【题目】4 If a is divisible byb, then a is called aof b, and b is called aof a. 相关知识点: 试题来源: 解析 【解析】multiple 反馈 收藏
运用多项式的除法易将原数因式分解为 2^555+1=(2^5+1)*(2^550-2^545+2^540……-2^5+1)=33*(2^550-2^545+2^540……-2^5+1)得证!
证明：数学归纳法 1，当n=1时，原式=13^n-6^n=13-6=7，可以被7整除 2，假设，n=m时，原式=13^m-6^m可以被7整除，3，当n=m+1时，原式=13^(m+1)-6^(m+1)=13*13^m-6*6^m =(7+6)*13^m-6*6^m =7*13^m+6*13^m-6*6^m =7*13^m+6(13^m-6^m)因为，7*...
Repeat steps 1 and 2 as many times as you need, until you get a single number. (9) Step 4 Find out what that single number is. The original number is divisible evenly only if your end sum is nine. In this example, 189 would be divisible by 9 because the single number was 9. ...