这不,前不久就用一道“invert a binary tree"干掉了homebrew的初创者Max Howell。 随着Max在twitter上吐槽(原推),这个”invert a binary tree"分分钟就火了。 Google: 90% of our engineers use the software you wrote (Homebrew), but you can’t invert a binary tree on a whiteboard so fuck off. L...
难倒大神的反转二叉树(Invert Binary Tree) Google作为大公司,果然有创造大新闻的潜质。这不,前不久就用一道“invert a binary tree"干掉了homebrew的初创者Max Howell。 随着Max在twitter上吐槽( 原推),这个”invert a bina… Twikn...发表于Hello... 数据结构: B-Tree 的删除 Cailiang MySQL Btree 顺...
Google: 90% of our engineers use the software you wrote (Homebrew), but you can’t invert a binary tree on a whiteboard so f*** off. 方法一:递归 时间复杂度:o(n) 空间复杂度:o(1)
# Definition for a binary tree node. # class TreeNode(object): # def __init__(self, x): # self.val = x # self.left = None # self.right = None class Solution(object): def invertTree(self, root): """ :type root: TreeNode :rtype: TreeNode """ if not root: return None s...
invertBinaryTree(BTree[root].rchild); } 1. 2. 3. 4. 5. 6. 这里的坑点是怎样寻找二叉树的根结点: 根据性质,二叉树根节点是只有出度没有入度的,所以在插入节点时,给每个子节点上一个不是根节点的标记,最后没有被上标记的那个就是根节点
Invert a binary tree. Example: Input: 4 / \ 2 7 / \ / \ 1 3 6 9 Output: 4 / \ 7 2 / \ / \ 9 6 3 1 复习时还不会的地方:没啥了,就加个null的判断条件就行了 [暴力解法]: 时间分析: 空间分析: [优化后]: 时间分析: ...
Google: 90% of our engineers use the software you wrote (Homebrew), but you can’t invert a binary tree on a whiteboard so fuck off. 这道题让我们翻转二叉树,是树的基本操作之一,不算难题。最下面那句话实在有些木有节操啊,不知道是Google说给谁的。反正这道题确实难度不大,可以用递归和非递归...
Invert a binary tree. 4 / 2 7 / \ / 1 3 6 9 to 4 / 7 2 / \ / 9 6 3 1 我以为很难,原来还是递归 网友说,递归不难,是一种思想。我认同,原来认为递归难,是因为还不具备用递归解决问题的习惯和思维方式。一旦把问题交给递归解决,发现竟然很省心。对,就是省心二字。
* Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */publicclassSolution{publicTreeNodeinvertTree(TreeNoderoot){if(root==null)returnroot;else{invertTree(root.left);invertTree(root.right...
Invert the Binary Tree | Problem Description Given a binary tree A, invert the binary tree and return it. Inverting refers to making left child as the right child and vice versa. Problem Constraints 1 <= size of tree <= 100000 Input Format First and only