当我把语言改为kotlin的时候,新建项目,报了错误,invalid type code: 00 并且导致我的程序无法运行。 解决方案:File -> Setting -> Languages & Frameworks -> Android(Experimental) ,取消两个勾选,skip soutce...and only sync... 参考网址:https://stackoverflow.com/questions/52570334/how-can-i-fix-thi...
16 java.io.StreamCorruptedException: invalid type code: 00 5 de/serialize java objects across different applications using different package names 1 Exception: java.io.StreamCorruptedException: invalid type code: 00 0 StreamCorruptedException: invalid type code: 00 Related 1 Java serialization ...
1、删除项目中的.gradle和.idea文件；2、点击File -> Invalidate Caches / Restart -> Invalidate and...
7 Serialization in Java, invalid type code 00 0 Writing/Reading an object(socket in java) 0 StreamCorruptedException: invalid type code: 00 Related 45 StreamCorruptedException: invalid type code: AC 16 java.io.StreamCorruptedException: invalid type code: 00 0 java.io.StreamCorruptedE...
Cause: invalid type code: 00 Consult IDE log for more details (Help | Show Log) (315 ms)...
openedonOct 5, 2023 This happens when the build server tries to get the customized model via Tooling API. When this exception occurs, it usually means that the Java version used by the Gradle Daemon and the Java version of the client which calls the TAPI are not matching. Then, when doin...
ObjectOutputStream后再重新打开往文件里面写对象时(append方式),就会再一次把“AC ED 00 05”写入文件,而这些信息并不是你写入对象的数据,所以当你用ObjectInputStream来读取对象时,流会将除第一个“AC ED 00 05”以外的数据当作各个对象的数据,造成无法解析,所以读取时有一个java.io.StreamCorruptedException出现...
Stuart Brown CreatedMay 17, 2021 14:16 There seems to be a bug in IJ, whenever I import my gradle projects, it can't build them, it doesn't pick up settings in my gradle.properties file and IJ log shows "java.io.StreamCorruptedException...
对于ObjectInputStream和ObjectOutputStream来说,在构造后的第一次读取或写入时,会先读取或写入一个对象头,之后再读取或写入对象。所以:只要有任意一方多次封装了对象流,就会造成重复加header或者重复去header,导致错误。 源码解析:ObjectOutputStream 下面圈出的位置会写入一个头:AC ED 00 05 ...
对于ObjectInputStream和ObjectOutputStream来说,在构造后的第一次读取或写入时,会先读取或写入一个对象头,之后再读取或写入对象。所以:只要有任意一方多次封装了对象流,就会造成重复加header或者重复去header,导致错误。 源码解析:ObjectOutputStream 下面圈出的位置会写入一个头:AC ED 00 05 ...