#计算出A和B两个链表的长度分别为m、n; #长度长的链表先走m-n步,之后再一次遍历寻找 #方法2: #先走到一个链表的尾部,从尾部开始走; #跳到另一个链表的头部 #如果相遇,则相遇点为重合节点 class Solution(object): def getLinkLenth(self,head): lenth=0 while head!=None: lenth+
Maintain two pointers pA and pB initialized at the head of A and B, respectively. Then let them both traverse through the lists, one node at a time. When pA reaches the end of a list, then redirect it to the head of B (yes, B, that's right.); similarly when pB reaches the end...
链接:https://leetcode-cn.com/problems/intersection-of-two-linked-lists python # 160.相交链表 # https://leetcode-cn.com/problems/intersection-of-two-linked-lists/solution/intersection-of-two-linked-lists-shuang-zhi-zhen-l/ class ListNode: def __init__(self, val): self.val = val self.ne...
Learn how to find the intersection of two arrays in Python with our step-by-step guide and example code.
Learn how to find the intersection of two linked lists in Python with this detailed guide, complete with examples and explanations.
解决Python intersection 和union的具体操作步骤 Python Intersection and Union Python provides built-in functions to find the intersection and union of two sets or lists. These functions areintersectionandunion. In this article, we will explore these functions and see how they can be used in various...
Leetcode 160. Intersection of Two Linked Lists 技术标签: Leetcode文章作者:Tyan 博客:noahsnail.com | CSDN | 简书 1. Description 2. Solution Version 1 Version 2 Reference https://leetcode.com/problems/intersection-of-two-linked-lists/description/......
Initially, we will take two lists from the user which may have repeated numbers or not. We will take the bitwise or (|) between the sets of both arrays to find union and assign it into a variable A in the form of lists. To find the intersection of both arrays, we will use the ...
If the two linked lists have no intersection at all, return null. The linked lists must retain their original structure after the function returns. You may assume there are no cycles anywhere in the entire linked structure. Your code should preferably run in O(n) time and use only O(1) ...
is 8 (note that this must not be 0 if the two lists intersect). From the head of A, it reads as [4,1,8,4,5]. From the head of B, it reads as [5,0,1,8,4,5]. There are 2 nodes before the intersected node in A; There are 3 nodes before the intersected node in B....