while headB: listB.append(headB.val) headB=headB.next minlen=len(listA) if len(listA)<len(listB) else len(listB) print listA,listB,minlen if listA[-1]!=listB[-1]:return None for i in xrange(1,minlen+1): print i if listA[-i]!=listB[-i]: return ListNode(listA[-i+1])...
Maintain two pointers pA and pB initialized at the head of A and B, respectively. Then let them both traverse through the lists, one node at a time. When pA reaches the end of a list, then redirect it to the head of B (yes, B, that's right.); similarly when pB reaches the end...
15. 用set来把list的重复元素过滤掉,然后判断是否存在,把结果保存起来 http://www.waitingfy.com/archives/3724
Learn how to find the intersection of two arrays in Python with our step-by-step guide and example code.
Suppose we have two sorted linked lists L1 and L2, we have to make a new sorted linked list which contains the intersection of these two lists. So, if the input is like L1 = [2, 4, 8] L2 = [3, 4, 8, 10], then the output will be [4, 8, ] To solve this, we will ...
python 内置的linkedlist python list intersection 1. 什么是列表 列表是一个可变的数据类型 列表由[]来表示, 每一项元素使用逗号隔开. 列表什么都能装. 能装对象的对象. 列表可以装大量的数据 2. 列表的索引和切片 列表和字符串一样. 也有索引和切片. 只不过切出来的内容是列表...
a = a ? a->next : headB; b = b ? b->next : headA; } returna; } }; 类似题目: [LeetCode] 349. Intersection of Two Arrays 两个数组相交 [LeetCode] 350. Intersection of Two Arrays II 两个数组相交II All LeetCode Questions List 题目汇总...
class Solution(object): def intersection(self, nums1, nums2): """ :type nums1: List[int] :type nums2: List[int] :rtype: List[int] """ return list(set(nums1) & set(nums2)) Solution 2: brute-force searching, search each element of the first list in the second list. (to be...
使用Python,我想检查一个列表是否包含另一个列表中也存在的项目/值。例如,这就是我要做的: list1 = ['item1','item2','item3'] list2 = ['item4','item5','item3'] if list1 contains any items also in list2: print("Duplicates found.") else: print("No duplicates found.") 你可以看到...
Write a program to find the node at which the intersection of two singly linked lists begins. 如下面的两个链表: 在节点 c1 开始相交。 示例1: 输入:intersectVal =8, listA = [4,1,8,4,5], listB = [5,0,1,8,4,5], skipA =2, skipB =3输出:Reference of the node with value =8...