【leetcode python】Intersection of Two Arrays #-*- coding: UTF-8 -*- #求两个集合的交集 class Solution(object): def intersection(self, nums1, nums2): resultList=list(set(nums1).intersection(set(nums2))) return resultList sol=Solution() print sol.intersection(nums1 =[1, 2, 2, 1]...
349. Intersection of Two Arrays&&350. Intersection of Two Arrays II,程序员大本营,技术文章内容聚合第一站。
一、前言 做了两题才慢慢摸清了leetcode的操作。 二、题349 Intersection of Two Arrays Given two arrays, write a function to compute their intersection. classSolution(object):defintersection(self, nums1, nums2):""":type nums1: List[int] :type nums2: List[int] :rtype: List[int]"""nums3...
python 两个数组的交集 intersection of two arrays,给定两个数组,写一个函数来计算它们的交集。例子:给定num1=[1,2,2,1],nums2=[2,2],返回 [2].提示:每个在结果中的元素必定是唯一的。我们可以不考虑输出结果的顺序。classSolution(object):defintersection(self,nums1,n
Learn how to find the intersection of two arrays in Python with our step-by-step guide and example code.
A program that demonstrates the intersection of two sorted arrays in Java is given as follows. Example Live Demo public class Example { public static void main(String args[]) { int arr1[] = {2, 4, 6, 8, 9}; int arr2[] = {1, 3, 4, 5, 6, 8, 9}; int m = arr1.length...
【leetcode76】Intersection of Two Arrays II 题目描述: 给定两个数组求他们的公共部分,输出形式是数组,相同的元素累计计数 例如: nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2]. 原文描述: Given two arrays, write a function to compute their intersection. Example: Given nums1 = [...
Intersectionof Two Arrays https://leetcode.com/problems/intersection-of-two-arrays/Given two arrays, w i++ 数组 原创 mb63982c735c3d9 2022-12-13 16:02:20 78阅读 POJ 1410Intersection 题目大意: 题目意思很简单,就是说有一个矩阵是实心的,给出一条线段,问线段和矩阵是否相交 An example: line:...
Write a program to find the node at which the intersection of two singly linked lists begins. For example, the following two linked lists: A: a1 → a2 ↘ c1 → c2 → c3 ↗ B: b1 → b2 → b3 begin to intersect at node c1. ...
https://leetcode.com/problems/intersection-of-two-arrays-ii/ 把一个数组中的元素的元素对应到哈希表,key是值,value是出现的次数,然后对照哈希表遍历另一个数组,O(n)。 follow up的问题: 1. 两个数组都有序的话可以用双指针; 2. 把num1做成哈希表,数量比较少; ...