方法一:Java解法,HashSet 方法二:Python解法,set 日期[LeetCode]题目地址:https://leetcode.com/problems/intersection-of-two-arrays/Difficulty: Easy题目描述Given two arrays, write a function to compute their intersection.Example 1:Input: nums1 = [1,2,2,1], nums2 = [2,2] Output: [2] Exampl...
因为使用Arrays类的sort方法,所以时间复杂度是O(n log(n)),空间复杂度是O(n)。 publicint[]intersection3(int[] nums1,int[] nums2){ Set<Integer>set=newHashSet<>(); Arrays.sort(nums1); Arrays.sort(nums2);inti =0;intj =0;while(i < nums1.length && j < nums2.length) {if(nums1[i...
Find first non-repeated character in a string– Java Code Find Intersection of Two Arrays – Java Code In our previous approach, we have used two for loops to solve this problem. Let’s improve our solution to solve this problem in single loop. To solve this problem in single iteration, ...
Given two integer arrays nums1 and nums2, return an array of their intersection. Each element in the result must be unique and you may return the result in any order. Example 1: Input: nums1 = [1,2,2,1], nums2 = [2,2] Output: [2] Example 2: Input: nums1 = [4,9,5], ...
每天一算:Intersection of Two Arrays II leetcode上第350号问题:Intersection of Two Arrays II 给定两个数组,编写一个函数来计算它们的交集。 示例 1: 输入: nums1 = [1,2,2,1], nums2 = [2,2] 输出: [2,2] 示例 2: 输入: nums1 = [4,9,5], nums2 = [9,4,9,8,4] 输出: [4,9]...
Handling arrays is a fundamental aspect of programming in C, and operations like finding the union and intersection of two sorted arrays are common tasks that require both logical thinking and a good understanding of algorithms. The union of two arrays combines the elements of both arrays, removin...
1. 2. Example 2: Input: nums1 =[4,9,5], nums2 =[9,4,9,8,4] Output:[9,4] 1. 2. Note: Each element in the result must be unique. The result can be in any order. AC code: classSolution{public:vector<int>intersection(vector<int>&nums1,vector<int>&nums2){intlen1=nums1...
Intersection of Two Arrays Desicription Given two arrays, write a function to compute their intersection. Example 1: 代码语言:javascript 复制 Input:nums1=[1,2,2,1],nums2=[2,2]Output:[2] Example 2: 代码语言:javascript 复制 Input:nums1=[4,9,5],nums2=[9,4,9,8,4]Output:[9,4] ...
The result can be in any order. Follow up: What if the given array is already sorted? How would you optimize your algorithm? What ifnums1's size is small compared tonums2's size? Which algorithm is better? What if elements ofnums2are stored on disk, and the memory is limited such ...
Arrays.sort(nums1); Arrays.sort(nums2);inti =0;intj =0;while(i < nums1.length && j < nums2.length) {if(nums1[i] < nums2[j]) { i++; }elseif(nums1[i] > nums2[j]) { j++; }else{ list.add(nums1[i]); i++; ...