#先走到一个链表的尾部,从尾部开始走; #跳到另一个链表的头部 #如果相遇,则相遇点为重合节点 class Solution(object): def getLinkLenth(self,head): lenth=0 while head!=None: lenth+=1 head=head.next return lenth def getIntersectionNode(self, headA, headB): """ :type head1, head1: ListNode...
Maintain two pointers pA and pB initialized at the head of A and B, respectively. Then let them both traverse through the lists, one node at a time. When pA reaches the end of a list, then redirect it to the head of B (yes, B, that's right.); similarly when pB reaches the end...
链接:https://leetcode-cn.com/problems/intersection-of-two-linked-lists python # 160.相交链表 # https://leetcode-cn.com/problems/intersection-of-two-linked-lists/solution/intersection-of-two-linked-lists-shuang-zhi-zhen-l/ class ListNode: def __init__(self, val): self.val = val self.ne...
ListNode(int x) : val(x), next(NULL) {} }; //假定链表A长于链表B,lenMin为链表B的长度 ListNode *Check(ListNode *headA, int lenA, ListNode *headB, int lenB) { int dis = lenA - lenB; //让长链表先走,走到长度与短链表一致; while (headA != NULL && dis--) { headA = headA-...
根据CYC刷题顺序开始,链表第一题, 视频播放量 24、弹幕量 0、点赞数 1、投硬币枚数 0、收藏人数 0、转发人数 0, 视频作者 kodgv, 作者简介 ,相关视频:CYC链表3leetcode148 链表排序,CYC链表2leetcode206 反转链表,CYC树题2 leetcode543 二叉树直径,CYC树题1 leetcode1
Write a Python program to create two Counter objects from two lists and then compute their union, intersection, and difference, printing each result. Write a Python function to merge two Counters by taking the maximum count for each key and print the merged Counter. ...
A C++ library to compress and intersect sorted lists of integers using SIMD instructions compression algorithms simd integer-compression intersection simd-instructions Updated Jul 13, 2023 C++ Geri-Borbas / Unity.Library.eppz.Geometry Star 332 Code Issues Pull requests 2D Geometry for Unity. Su...
Language:python # Definition for singly-linked list.# class ListNode(object):# def __init__(self, x):# self.val = x# self.next = NoneclassSolution(object):defgetIntersectionNode(self,headA,headB):""" :type head1, head1: ListNode :rtype: ListNode """ifheadAisNoneorheadBisNone:retur...
If you want to get the intersection of arrays, use the intersect1d() method. Intersection means finding common elements between two arrays.
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