先将两数组排序,然后使用双指针,依次判断两数组中的元素是否相等,如果某个元素大于或小于另外一个元素,则将指针向后移动,如果相等,则将元素放入ArrayList中,然后将ArrayList中的元素迭代放入数组,最后返回。 因为使用Arrays类的sort方法,所以时间复杂度是O(n log(n)),空间复杂度是O(n)。 publicint[]intersect(int...
因为使用Arrays类的sort方法,所以时间复杂度是O(n log(n)),空间复杂度是O(n)。 publicint[]intersection3(int[] nums1,int[] nums2){ Set<Integer>set=newHashSet<>(); Arrays.sort(nums1); Arrays.sort(nums2);inti =0;intj =0;while(i < nums1.length && j < nums2.length) {if(nums1[i...
length2)];intindex=0;HashMap<Integer,Integer>map=newHashMap<Integer,Integer>();for(inti=0;i<length1;i++){if(!map.containsKey(nums1[i])){map.put(nums1[i],1);}else{map.put(num
Given two arrays, write a function to compute their intersection. Example: Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2]. Note: 1、Each element in the result must be unique. 2、The result can be in any order. 要完成的函数: vector<int> intersection(vector<int>& ...
1// 349. Intersection of Two Arrays 2// https://leetcode.com/problems/intersection-of-two-arrays/description/ 3// 时间复杂度: O(nlogn) 4// 空间复杂度: O(n) 5class Solution { 6public: 7 vector<int> intersection(vector<int>& nums1, vector<int>& nums2) { 8 9 set<int> record(...
https://leetcode.com/problems/intersection-of-two-arrays/discuss/81969/Three-Java-Solutions Given two arrays, write a function to compute their intersection. Example 1: AI检测代码解析 Input: nums1 =[1,2,2,1], nums2 =[2,2] Output:[2] ...
Find first non-repeated character in a string– Java Code Find Intersection of Two Arrays – Java Code In our previous approach, we have used two for loops to solve this problem. Let’s improve our solution to solve this problem in single loop. ...
leetcode【数组】---349. Intersection of Two Arrays(两个数组的交集),程序员大本营,技术文章内容聚合第一站。
【leetcode76】Intersection of Two Arrays II : Given two arrays, write a function to compute their intersection. Example: Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2]. Note: Each element in the result must be unique. The result can be in LeetCode编程练习 - Interse...
Intersection of Two Arrays 题目Given two arrays, write a function to compute their intersection. Note: Each element in the result must be unique. The result can be in any order. 解析 求两个数组的交集,如果用java中的set来实现的话,此题就没有什么难度。但是用C语言的话还是......