1828 1 1:59 App 求积分 Integral of (secx)^6 dx 7232 10 6:13 App 求不定积分 Integral of Power[tanx, (3)^-1] dx 2533 -- 3:40 App 求不定积分 ∫x Sqrt[1 - x^4] dx 3158 -- 3:37 App 求不定积分Integral of (Sqrt[cotx] - Sqrt[tanx]) dx 482 -- 226:06:49 App ...
1158 1 4:16 App 求不定积分 ∫(sec^2 x)/(secx + tanx)^(9/2) dx 1722 -- 5:32 App 求不定积分∫Sqrt[x^2 - 2 x + 2] dx 3248 2 3:01 App 比较简单的积分练习题 Integral of sin (lnx) dx 7643 6 4:32 App 求所有的质数 p, q ,满足 p^q + q^p 是质数 7224 10 3...
∫1secx+tanxdx= View Solution ∫secxlog(secx+tanx)dx= View Solution Free Ncert Solutions English Medium NCERT Solutions NCERT Solutions for Class 12 English Medium NCERT Solutions for Class 11 English Medium NCERT Solutions for Class 10 English Medium ...
Evaluate the integral: \int tan^{3}x\ secx\ dx. Find the integral of (-x^2 + 2x - 2)/(x^3 - 3x^2 + 2x) dx. Evaluate the indefinite integral. x arctan (4x) dx Evaluate the indefinite integral integral sec^4 x tan x dx Evaluate the integral: integral of tan^2...
Evaluate the indefinite integraL J (sin5x-cosx)dx = 1. 2. J sec x(secx-tanx)dx = 3. j (esc2x-x^dx = 4. J sin2xcosxdx = 5. jsec2xtan = 6. J sec2xdx = 7. 9. J严dx = JX 总 12.fSin v= J 1+cosx 13.f—1—=」x\nx ...
Answer and Explanation:1 We are given: {eq}\displaystyle \int_{0}^{\frac{\pi }{2}}\sin ^{3}\ x\cos ^{2}\ x \ dx {/eq} Compute the indefinite integral: {eq}=\displaystyle... Learn more about this topic: Applying the Rules of Differentiation to Calculate Derivatives ...
xsecxtanx Evaluate the integral. \displaystyle\int _ { 0 } ^ { \operatorname { ln } 4 } e ^ { 2 x } d x Evaluate the integral. \displaystyle\int \frac { 14 x + 40 } { \sqrt { x ^ { 2 } + 7 x - 1 } } d x Evaluate the integral. \displaystyle\int _ { 0 } ^...
常用积分表（Common integral table）Common integral formula (a) containing the integral (axb+0a =) Formula 1.dxaxb+ = 1lnaxbCa++ 2. = (axbx) + 11 (formula)(1)AxbCa + + + Mu + (U = 1.)3.dxxaxb+ = formula 21 (LN) axbbaxbCa+.++ The 4.2dxxaxb+ formula (2) = 22311 (...
函数secxtan 无法识别您的输入,请检查。不定积分计算器可以用分析整合的方法,计算出一个给定变量的函数的不定积分(原函数)。它也可以画出函数和它的原函数的图像。请注意,计算的不定积分属于一类函数F(x) C,其中C是任意常数。不定积分计算器解析表达式,应用积分法则并化简最终结果。因此,积分计算的最终结果可能...
Formula1.dxaxb+=1lnaxbCa++ 2.=(axbx)+11(formula) (1) AxbCa+++Mu + (U=1.) 3.dxxaxb+=formula 21(LN)axbbaxbCa+.++ The4.2dxxaxb+formula(2)=22311 (ln2axbbaxbbaxbCa..+.++++.)... Five (d) Formulaxxaxb+=1lnaxbCbx+ ...