求定积分 Integral of (sin^3 x)/(sin^3 x + cos^3 x) from 0 to pi/2 1.1万 21 04:35 App 有点难度的积分 Integral of x^2/(x sinx + cosx)^2 dx 1044 1 01:59 App 简单的几何问题,求长度 2461 0 01:56 App 中国为什么很难出大的数学家? 6284 22 04:10 App 有点难度的积分 Integ...
Integrate: integral of (sec^2 x)/(3 + tan^2 x) dx. Evaluate the following integral. (a) \int sec^2x \space tanx dx (b) \int (x^3 +x)^{10}(3x^2 + 1) dx Find the antiderivative of the following function. f(x) = tanx Integral of x tan(x^2) dx Evaluate the integral ...
3158 -- 3:37 App 求不定积分Integral of (Sqrt[cotx] - Sqrt[tanx]) dx 482 -- 226:06:49 App 普林斯顿高研院 视频合集 Ⅲ 6394 5 4:01 App 求不定积分Integral of (a*sinx + b*cosx)/(c*sinx + d*cosx) dx浏览方式(推荐使用) 哔哩哔哩 你感兴趣的视频都在B站 打开信息...
(1)xe^x-e^x+c(2)-xcosx+sinx+c(3)1/3x^3lnx-1/9x^3-c(4)-1/3πccos3x+1/9sin3x-c(5)1/2xsin2x⋅|1/4cos2x|c(6)xtanx+ln(cosx)+c(7)xlnx-x+c(8)x(lnx)^2-2xlnx+2x+c(9)αarctana1/2ln(a^2)1e 结果一 题目 Use integration by parts to find the integral of...
\int \frac{sin(tanx)}{cos^2x} dx Evaluate the integral of x(x + 5)^8 dx. Evaluate the integral of tan^(10)(x) sec^2(x) dx. Evaluate the integral of (x - 1/(2x))^2 dx. Evaluate: integral x^4 / (6-x^5)^7 dx Evaluate the integral, \int_{1}^{4} 4x(x^2-7)^...
59. [T] y=tanxy=tanx over the interval [0,π4][0,π4]; the exact solution is 2ln(2)π2ln(2)π.60. [T] y=x+1√4−x2y=x+14−x2 over the interval [−1,1][−1,1]; the exact solution is π6π6. Show Solution ...
∫cotxdx ln|sinx| + C ∫tanxdx -ln|cosx| + C ∫secxdx ln|secx + tanx| + C ∫e^u du e^u + C ∫cscxdx -ln|cscx+cotx| + C d/dx [a^x] (a^x) * ln a d/dx aᵘ aᵘ (ln a) du/dx d/dx [log a (x)] 1/(x * ln a) ∫a^x dx a^x/ln(a) + C d/dx...
NCERT solutions for CBSE and other state boards is a key requirement for students. Doubtnut helps with homework, doubts and solutions to all the questions. It has helped students get under AIR 100 in NEET & IIT JEE. Get PDF and video solutions of IIT-JEE Mains & Advanced previous year pap...
cot xdx = ln| sinx| + C, sec x = ln| sec x + tanx| + C, and csc xdx = ln| csc x − cot x| +C. 1. Logarithms: the adventure begins 1.1. Finding an antiderivative of the reciprocal function. Recall that the process of differentiation never gave us fundamentally new funct...
(iv)Si(x)hasstationarypointswhenSi′(x)=0.Lookingatthegraphagain,ornotingthat(sinx)/x=0preciselywhensinx=0(exceptatx=0)(we)ndthestationarypointsofSi(x)tobeatx=π,2π,and3π. (v)Addupthesquaresunderthegraphof(sinx)/xtoestimateSi(x),rememberingthat the area of each square is 0.2×0.2...