Sine integral Si(x) Syntaxdouble sin_integral( double x )Parametersx [input] the argument x of the functionReturnReturns the value of the sine integral Si(x) ExamplesEX1 void sin_integral_ex1() { double dx[5]= {0.2,0.4,0.6,0.8,1.0}; for(int ii = 0; ii<5 ; ii++) printf("%lf...
fun = @(x)sin((1:5)*x); q = integral(fun,0,1,'ArrayValued',true) q =1×50.4597 0.7081 0.6633 0.4134 0.1433 Improper Integral of Oscillatory Function Create the functionf(x)=x5e−xsinx. fun = @(x)x.^5.*exp(-x).*sin(x); ...
Define the anonymous function f(x,y,z)=ysinx+zcosx. Get fun = @(x,y,z) y.*sin(x)+z.*cos(x) fun = function_handle with value: @(x,y,z)y.*sin(x)+z.*cos(x) Integrate over the region 0≤x≤π, 0≤y≤1, and −1≤z≤1. Get q = integral3(fun,0,pi,0,1...
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\sin (y^2 - x^3). \end{aligned}$$ with the weight function \(\theta _{\varepsilon }^{\vardelta }\in \mathcal {w}_1\) , the quadrature error has an upper bound estimate \(\mathcal {o}(h^{\frac{1}{2} + 2(1 - \alpha )})\) . as we can see in fig. 2 , ...
The composite trapezoidal rule for the computation of Hadamard finite-part integrals in boundary element methods with the hypersingular kernel 1/sin 2(x-s) is discussed,and the main part of the asymptotic expansion of error function is obtained.Based on the main part of the asymptotic expansion...
Da aus der Konvergenz des uneigentlichen Integrals[Math Processing Error]∫1∞sin(t2)dtdie von [Math Processing Error]∫0∞sin(t2)dt=∫01sin(t2)dt+∫1∞sin(t2)dt folgt, da die Funktion stetig auf [0, 1] ist. ...
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Consider the Pearson correlation coefficient between the two functions \(\cos (x)\) and \(\sin (x)\) over the interval \((0,\pi /2)\). The expected Pearson correlation coefficient between these two series can be estimated by discrete sampling in the limiting case of an infinite number ...