1. 解释错误消息 "size of array ‘altstackmem’ is not an integral constant-expression" 的含义 这个错误消息表明在尝试定义一个数组 altstackmem 时,其大小不是一个整数常量表达式。在C或C++中,数组的大小必须在编译时是已知的,且必须是一个常量表达式。这意味着数组的大小不能是一个变量或者一个需要在运行...
An integral constant expression that evaluates to zero is converted to a pointer called the "null pointer." This pointer is guaranteed to compare unequal to a pointer to any valid object or function (except for pointers to based objects, which can have the same offset and still point to diff...
Re: size of array is not an integral constant-expression johnehein@gmail .com wrote: #include <vector> using namespace std; > template <typename Iter> int foo(Iter first, Iter last, int nn) { const size_t n = last - first; double buf[n]; return 0; } > int main(int argc, cha...
百度试题 结果1 题目error C2058: constant expression is not integral 中文对照:(编译错误)常量表达式不是整数相关知识点: 试题来源: 解析 分析:一般是定义数组时数组长度不是整型常量 反馈 收藏
If a static data member is of const integral or const enumeration type, its declaration in the class definition can specify a constant-initializer which shall be an integral constant expression 所以不只整型常量可以,枚举常量也可以在类中初始化,像下面这样 ...
https://developer.aliyun.com/profile/5yerqm5bn5yqg?spm=a2c6h.12873639.0.0.6eae304abcjaIB ...
@@ -66,7 +66,8 @@ namespace AssetBundler AZ::Data::AssetInfo assetInfo; QString platformList; const auto& enabledPlatforms = AzToolsFramework::PlatformAddressedAssetCatalogManager::GetEnabledPlatforms(); AZ_Error(AssetBundler::AppWindowName, !enabledPlatforms.empty(), "Unable to find any enabl...
If a static data member is of const integral or const enumeration type, its declaration in the class definition can specify a constant-initializer which shall be an integral constant expression 所以不只整型常量可以,枚举常量也可以在类中初始化,像下面这样 ...
The ISO C compiler warns you, when you use the -xtransition option, about any expression whose behavior might change according to the typing rules of the constants involved. The old integral constant typing rules are used only in the transition mode; the ISO and conforming modes use the new...
const int WIDTHMSB = log2(WIDTH)-1; sc_uint<WIDTHMSB\+1> id; Vivado reports a error: error: non-type template argument of type 'int' is not an integral constant expression sc_uint<WIDTHMSB\+1> id; ^~~~ Is there any other way to define a inte...