What is the total number of integers between 100 and 200 that are divisible by 3? (分数:5.00) A. 33 √ B. 32 C. 31 D. 30 E. 29 相关知识点: 试题来源: 解析 解析:对于区间[a,b]中有多少个数能够被数n整除,计算方法如下:第一步:把b往小里凑。找到最近的n的
在1至100,且包括1和100的整数中,若能被2整除(divisible),就被放入A列中,若能被3整除就被放入B列中,有多少数在A列中而不在B列中 1至100中能被2整除的数显然是50个,那么如何算能够被3整除的数呢 在小于或等于100的正整数中能被3整除的最大的数是3的多少倍.就有多少个数能被3整除。在1至100中能被...
, Integers divisible by sums of powers of their prime factors, J. Number Theory 128 (2008), 557-563.J.-M. De Koninck and F. Luca, Integers divisible by sums of powers of their prime factors, J. Number Theory 128 (2008), 557-563....
On her walk today, Emma walked along a straight path between the entrance to her house, H, and the entrance to library, L, passing a crosswalk sign, J, and then a crosswalk sign, K. First Emma walked from H to J and then tu...
GMAT 考满分题库If x and y are integers, is xy+ 1 divisible by 3 ?[br/[ 1.When x is divided by 3, the remainder is 1.2.When y is divided by 9, the remainder is 8.
则四位正整数一共有个, 能被整除的最小四位正整数是, 能被整除的最大四位正整数是, 则能被整除的四位正整数有个, 能被和同时整除的最小四位正整数是, 能被和同时整除的最大四位正整数是, 则能被和同时整除的四位正整数有个, , 故有个四位正整数可被整除但是不可被整除.反馈...
CWrite out the product of five consecutive integers and call their product P . Then P=(n)(n+1)(n+2)(n+3)(n+4) . Note that exactly one of these numbers will be divisible by 5 , and at least one of these numbers will be divisible by 3 and 4. Either two or three of these ...
How many integers between 1 and 200 are multiples of both 3 and 5 but not of either 4 or 7? How many integers between 504 and 1188 are multiples of 6? What is the number of integers from (999, 9999) that are divisible by 4 and are not divisible by 5?
What is the sum of all the odd integers from 1 to 50? The sum of five consecutive integers is 95. What are the five integers? The sum of two consecutive integers is between 5 and 9. What are the two integers? The sum of three consecutive integers is 99. What are the three integers...
I want to find number of integers from 1 to 19 (both included) which are divisible by 2 or 3 or 4. Lets denote it by N. So counting and enumerating them givesN = 12. Integers are 2, 3, 4, 6, 8, 9, 10, 12, 14, 15, 16 and 18. ...