0010-regular-expression-matching.cpp 0011-container-with-most-water.cpp 0012-integer-to-roman.cpp 0013-roman-to-integer.cpp 0014-longest-common-prefix.cpp 0015-3sum.cpp 0017-letter-combinations-of-a-phone-number.cpp 0018-4sum.cpp 0019-remove-nth-node-from-end-of-list.cpp 0020-valid-parenthese...
sum = sum + m[str[i +1]]; } else { // m[i]<m[i+1], then add m[i+1] to sum, and remove 2*m[i] sum = sum + m[str[i +1]] -2* m[str[i]]; } } returnsum; } #defineMAX3999 // integer to roman string integer2roman(unsignedintn) { // we should consider 4,...
0012-integer-to-roman.cpp 0013-roman-to-integer.cpp 0014-longest-common-prefix.cpp 0015-3sum.cpp 0017-letter-combinations-of-a-phone-number.cpp 0018-4sum.cpp 0019-remove-nth-node-from-end-of-list.cpp 0020-valid-parentheses.cpp 0021-merge-two-sorted-lists.cpp 0022-generate-parentheses.cpp 00...
【Roman To Integer】cpp 题目: Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. 代码: class Solution { public: int romanToInt(string s) { const int size = ; std::map<char, int> symbol_value; char symbol_ori[size] = {'...
LeetCode-Easy-Roman To Integer ###原题目 将I V C M 诸如此类的罗马数字输入后,转换成数字输出。 ```cpp Example Symbol Value I 1 V 5 X 10 L 50 C 100 D 500 M 1000 Example 1: Input: "III" Output: 3 Example 2: Input: "IV"...
integer-to-roman 开发技术 - 其它 Sc**tt上传4KB文件格式zip 整数到罗马 该项目的目的是将整数(整数)转换为其罗马数字。 例如,数字1990是罗马数字中的MCMXC。 用户体验 作为用户,如果我输入小于1或大于3999的数字,则会收到错误消息: Invalid input. Please enter a whole number between 1 and 3999....
Write a program rootTable.cpp which reads in the number of roots, a value increment, and a precision and outputs a table of roots: x 1/2 , x 1/3 , ? for the given number of roots and values of x equ Write a C program to display a...
更新于 6/9/2020, 7:04:30 PM cpp 根据罗马数字的计数规则进行转换即可. class Solution { public: /** * @param n The integer * @return Roman representation */ string intToRoman(int n) { string ans; string Roman[] = {"M", "CM", "D", "CD", "C", "XC", "L", "XL", "X"...
更新于 6/9/2020, 7:04:31 PM cpp 根据罗马数字的计数规则, 模拟运算即可. class Solution { public: int romanToInt(string s) { int ans = 0; ans = toInt(s[0]); for (int i = 1; i < s.length(); i++) { ans += toInt(s[i]); if (toInt(s[i-1]) < toInt(s[i])) ...
// RomanToInteger.cpp : 定义控制台应用程序的入口点。 // #include "stdafx.h" #include #include <iostream> usingnamespacestd; classSolution { public: intromanToInt(string s) { map<char,int>romanMap; romanMap['I'] = 1; romanMap...