int ans=0; public int Nqueen (int n) { //在build()中,放置第i个皇后 int[] arr=new int[n];//arr[i]表示第i个皇后在第j列 build(0,n,arr);//放置第0个皇后,总共放置n个皇后,arr[n]表示第n个皇后的列数 return ans; } public void build(int i,int n,int[] arr){ if(i==n){ ...
#include iostream using namespace std;int ans = 0;int i;if (n ==1)return 1;for (i = x; i = m / n; i++)ans += g(m- i, n - 1, i);return ans;}int main(){int t, m, n;cin m n;cout g(m, n, 0) endl;return 0;}输入:84输出: 相关知识点: 试题来源: 解...
#include <iostream>using namespace std;int g(int m, int n, int x) { int ans = 0; int i; if (n == 1) return 1; for (i = x; i <= m / n; i++) ans += g(m - i, n - 1, i); return ans;}int main() { int t, m, n; cin >> m >> n; cout << g(...
int main(){ int n = 0, ans = 0; cin gt;gt; n; ans = 0; while (n + 1){ ans++; n = n | (n + 1); } cout lt;lt; ans lt;lt; endl; _牛客网_牛客在手,offer不愁
intp1 =std::lower_bound(all(goright), x)-goright.begin-1;intp2 =std::lower_bound(all(goright),x-2*T)-goright.begin;ans += p1-p2+1; }printf("%lld\n",ans);return0;} E 参考代码 #include<bits/stdc++.h> #definefi first#definese second#defineDB double#defineU unsigned#define...
(1<<30);constintroot =1;charss[210] = {0};charss2[205] = {0};intact =1, co =1;intacteg =-1;inttep =0;intind =0, rem =0, s_end =-1;intlinks[205] = {0};intvv[205] = {0};intmm =0;intlinkk =0;intlen1 =0, len2 =0;intans =0;structab{intl;intr;intnex;...
intsum[N][N] = {0}; intgetSum(intx,inty,intk,intl){ intans = sum[k][l] - sum[k][y -1] - sum[x -1][l] + sum[x -1][y -1]; returnans * ans; } intmin(intx,inty){ returnx < y ? x : y; } 初始化
memset( cnt,0,sizeof(int)*(SAM.ant+4) );intans =0; cnt[1] =1;for(inti =1; i <= SAM.ant; ++i ) {intu =r[i];if( i >1&& !cnt[u] )continue; ans= ( ans + sum[u] ) %MOD;for(intj =0; j <10; ++j )
使用方式 声明定义 与其他类型一致 类型名 变量名 __int128 a=4,b=3; a=10; a+=b; a*=b; ...输入 void read(__int128 &ans){ __int128 x,f=1; char ch=getchar(); while(ch'9'){...x){ if(x<0){ putchar('-'); x*=-1; } int ans[35]={0},top=0; do{ ans[top++...