$$\int_0^{\pi} \sin x\,dx=[-\cos x]_0^{\pi}=-\cos\pi-(-\cos 0)=2.$$ 所以,$\int_0^{\pi} \sin x\,dx=2$。 开学特惠 开通会员专享超值优惠 助力考试高分,解决学习难点 新客低价 最低仅0.1元开通VIP 百度教育商务合作 产品代理销售或内容合作等 立即合作 题目 反馈 收藏 有用...
设$$ I = \int _ { 0 } ^ { \frac { \pi } { 4 } } \ln \sin x d x , J = \int _ { 0 } ^ { \frac { \pi } { 4 } } \ln \cot x d x , K = \int _ { 0 } ^ { \frac { \pi } { 4 } } \ln \cos x d $$ ,则I,J,K的大小关系是(...
NCERT solutions for CBSE and other state boards is a key requirement for students. Doubtnut helps with homework, doubts and solutions to all the questions. It has helped students get under AIR 100 in NEET & IIT JEE. Get PDF and video solutions of IIT-JEE Mains & Advanced previous year pap...
参数和值类型 使用字符串运算符和通配符 财务函数选择提示 用于对值四舍五入的函数 接受条件和通配符作为参数的函数 数字函数 ABS CEILING COMBIN EVEN EXP FACT FACTDOUBLE FLOOR GCD INT LCM LN LOG LOG10 MOD MROUND MULTINOMIAL ODD PI POLYNOMIAL POWER ...
NCERT solutions for CBSE and other state boards is a key requirement for students. Doubtnut helps with homework, doubts and solutions to all the questions. It has helped students get under AIR 100 in NEET & IIT JEE. Get PDF and video solutions of IIT-JEE Mains & Advanced previous year pap...
【解析】定积分 ∫_0^πsinxdx=(-cosx)|_0^π=1+1=2故答案为:2.【定积分的概念】一般地,如果函数f(x)在区间[a,b]上连续,用分点a=x_0x_1⋅⋅⋅x_(i-1)x_i⋅⋅⋅x_n=b 将区间 [a,b] 等分成n个小区间,在每个小区间[x.x]上任 ξ_i(i=1,2,⋯,n) (=12 ∑...
【题目】设f(x)在[0,π]上连续.证明:$$ \int _ { 0 } ^ { \pi } x f ( \sin x ) d x = \frac { \pi } { 2 } \int _ { 0 } ^ { \pi } f ( \sin x ) d x = \pi \int _ { 0 } ^ { \frac { \pi } { 2 } } f ( \sin x ) d x $$...
NCERT solutions for CBSE and other state boards is a key requirement for students. Doubtnut helps with homework, doubts and solutions to all the questions. It has helped students get under AIR 100 in NEET & IIT JEE. Get PDF and video solutions of IIT-JEE Mains & Advanced previous year pap...
Each column of X is one pulse. Example: sin(pi./[32 32].*(0:2047)')+randn(2048,2)/10 Data Types: double METHOD— Pulse integration method "noncoherent" (default) | "coherent" Pulse integration method, specified as "coherent" or "noncoherent". METHOD is the method used to integrate...
If∫π0xf(sinx)dx=a∫π0f(sinx)dx, then a = View Solution ∫π0dx1−sinx= View Solution ∫π0sin(2⋅x)dx View Solution Doubtnut is No.1 Study App and Learning App with Instant Video Solutions for NCERT Class 6, Class 7, Class 8, Class 9, Class 10, Class 11 and Class 12...