Java参考代码: AI检测代码解析 /** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { * val = x; * next = null; * } * } */ public class Solution public ListNode insertionSortList(ListNode head) { if (head == null) ...
1、题目描述 2、题目分析 利用插入排序的算法即可。注意操作指针。 3、代码 1ListNode* insertionSortList(ListNode*head) {2if(head == NULL || head->next ==NULL)3returnhead;45ListNode *dummy =newListNode(0);6dummy->next =head;7ListNode *pre =dummy;8ListNode *p =head;9ListNode *pn = head-...
Insertion Sort就是把一个一个元素往已排好序的list中插入的过程。 初始时,sorted list是空,把一个元素插入sorted list中。然后,在每一次插入过程中,都是找到最合适位置进行插入。 因为是链表的插入操作,需要维护pre,cur和next3个指针。 pre始终指向sorted list的fakehead,cur指向当前需要被插入的元素,next指向下...
public class Solution { public ListNode insertionSortList(ListNode head) { // 先写最特殊的情况 if (head == null) { return null; } ListNode dummyNode = new ListNode(-1); dummyNode.next = head; ListNode curNode = head; ListNode pre; ListNode next; while (true) { // 如果遍历下去,是...
Can you solve this real interview question? Insertion Sort List - Given the head of a singly linked list, sort the list using insertion sort, and return the sorted list's head. The steps of the insertion sort algorithm: 1. Insertion sort iterates, con
* Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode* insertionSortList(ListNode* head) { ListNode*...
Now comes the code: 1classSolution {2public:3ListNode* insertionSortList(ListNode*head) {4ListNode* new_head =newListNode(0);5new_head -> next =head;6ListNode* pre =new_head;7ListNode* cur =head;8while(cur) {9if(cur -> next && cur -> next -> val < cur ->val) {10while(pre...
将cur->next插入到pre之后,这里需要四个步骤,需要特别小心! 如上图所示,将cur->next插入到pre节点后大致分为3个步骤。 最好情况下时间复杂度降至O(n), 其他同题解1. Reference Explained C++ solution (24ms) - Leetcode Discuss Insertion Sort List - 九章算法...
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总结: sort list using insertion sort ** Anyway, Good luck, Richardo! My code: /** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { val = x; } * } */publicclassSolution{publicListNodeinsertionSortList(ListNode head){if...