AI代码解释 publicclassInsertionSort{publicstaticvoidmain(String[]args){int[]array={4,2,8,3,1};insertionSort(array);System.out.println(Arrays.toString(array));}publicstaticvoidinsertionSort(int[]array){int n=array.length;for(int i=1;i<n;i++){int key=array[i];int j=i-1;// Move ...
it will still execute the outer for loop thereby requiring n number of steps to sort an already sorted array. This makes the best time complexity of insertion sort a linear function of N where N is the number of elements in the array. ...
直接插入排序(Insertion Sort) 基本思想 将待排序的无序数列看成是一个仅含有一个元素的有序数列和一个无序数列,将无序数列中的元素逐次插入到有序数列中,从而获得最终的有序数列。 算法流程 初始时, a [ 0 ] a[0]a[0]自成一个有序区, 无序区为a [ 1 , . . . , n − 1 ] a[1, ... ...
1//C语言实现2voidinsertionSort(intarray[],intnum)3{4//正序排列,从小到大5for(inti =1; i < num; i++)6{7intkey =array[i];8intj =i;9while(j >0&& array[j -1] >key)10{11array[j] = array[j -1];//向有序数列插入时,如果大于key,则向后移动12j -- ;//位置向前移动判断下一...
}voidtest(vector<int>arr){//输出原始序列print_array("original array:",arr.data(),arr.size());//执行排序,并输出排序过程InsertSort(arr.data(),arr.size());//输出排序后的列表print_array("after sorted:",arr.data(),arr.size());cout<<endl;}intmain(){test({1});test({1,2});test(...
/*Insertion Sort - C program to sort an Arrayin Ascending and Descending Order.*/#include<stdio.h>#defineMAX 100intmain(){intarr[MAX],limit;inti,j,temp;printf("Enter total number of elements:");scanf("%d",&limit);/*Read array*/printf("Enter array elements:\n");for(i=0;i<limit...
C - Insertion Sort(数学规律题, 递推) Insertion sort is a simple sorting algorithm that builds the final sorted array one item at an iteration. More precisely, insertion sort iterates, consuming one input element each repetition, and growing a sorted output list. At each iteration, insertion ...
Problem Statement Given an array of integers, sort the array in ascending order using an optimized version of the insertion sort algorithm that utilizes only one loop. Approach The traditional insertion sort algorithm shifts elements one by one to their correct position. In my optimized version, I...
CF362C Insertion Sort树状数组,思维,枚举 题意:先交换任意两个,然后只能交换相邻两个,问最少操作次数和方案。 思路:由于冒泡排序有个定理就是逆序数的个数等于最少的交换相邻元素的次数,问题就转换为了交换两个数并且使得整个数组逆序数个数最少,我们枚举交换哪两个数,用树状数组处理b[i][j],f[i][j],i...
[i]; } SortArray(arr, size);//Call function to sort arrayfor(inti = 0; i < size; i++) { cout <<"The value at index "<< i <<" is: "<< arr[i] << endl; }delete[] arr;//<--Call delete when we are done using the memory since we used new to allocate that memory. ...