You are given therootnode of a binary search tree (BST) and avalueto insert into the tree. Returnthe root node of the BST after the insertion. It isguaranteedthat the new value does not exist in the original BST. Noticethat there may exist multiple valid ways for the insertion, as lon...
给定二叉搜索树(BST)的根节点和要插入树中的值,将值插入二叉搜索树。返回插入后二叉搜索树的根节点。保证原始二叉搜索树中不存在新值。 Given the root node of a binary search tree (BST) and a value to be inserted into the tree, insert the value into the BST. Return the root node of the BST...
LeetCode 701. Insert into a Binary Search Tree (二叉搜索树中的插入操作) 题目 链接 https://leetcode.cn/problems/insert-into-a-binary-search-tree/ 问题描述 给定二叉搜索树(BST)的根节点 root 和要插入树中的值 value ,将值插入二叉搜索树。 返回插入后二叉搜索树的根节点。 输入数据 保证 ,新值和...
Given the root node of a binary search tree (BST) and a value to be inserted into the tree, insert the value into the BST. Return the root node of the BST after the insertion. It is guaranteed that the new value does not exist in the original BST. Note that there may exist multipl...
[leetcode] 701. Insert into a Binary Search Tree Description You are given the root node of a binary search tree (BST) and a value to insert into the tree. Return the root node of the BST after the insertion. It is guaranteed that the new value does not exist in the original BST....
LeetCode-701. Insert into a Binary Search Tree Given the root node of a binary search tree (BST) and a value to be inserted into the tree, insert the value into the BST. Return the root node of the BST after the insertion. It is guaranteed that the new value does not exist in ...
源代码以及文字版解题思路 https://maxming0.github.io/2020/10/06/Insert-into-a-Binary-Search-Tree/YouTube: https://www.youtube.com/channel/UCdSmtAmcHSc-V-5FhVidFrQbilibili: https://space.bilibili.com/478428905如果喜欢我, 视频播放量 81、弹幕量 0、点赞数 5、
0904-fruit-into-baskets 0905-sort-array-by-parity 0912-sort-an-array 0922-sort-array-by-parity-ii 0931-minimum-falling-path-sum 0934-shortest-bridge 0938-range-sum-of-bst 0941-valid-mountain-array 0946-validate-stack-sequences 0958-check-completeness-of-a-binary-tree 0974-subarray-sums-divisib...
root.Left = insertIntoBST(root.Left, val) } return root }func main() { root := &TreeNode{ Val: 4, Left: &TreeNode{ Val: 2, Left: &TreeNode{ Val: 1, }, Right: &TreeNode{ Val: 3, }, }, Right: &TreeNode{ Val: 7, ...
*/class Solution{public:TreeNode*insertIntoBST(TreeNode*root,intval){TreeNode*insert=newTreeNode(val);if(!root){root=insert;returnroot;}TreeNode*current=root;TreeNode*pre=NULL;while(current){pre=current;if(current->val>val){current=current->left;}else{current=current->right;}}if(pre->val...