You are given a reference to the node with value 3, and we need to insert 2 into the list. The new node should be inserted between node 1 and node 3. After the insertion, the list should look like this, and we should still return node 3. Example 2: Input: head = [], insertVal...
Input: head = [3,4,1], insertVal = 2 Output: [3,4,1,2] Explanation: In the figure above, there is a sorted circular list of three elements. You are given a reference to the node with value 3, and we need to insert 2 into the list. The new node should be inserted between n...
Input: head = [3,4,1], insertVal = 2 Output: [3,4,1,2] Explanation: In the figure above, there is a sorted circular list of three elements. You are given a reference to the node with value 3, and we need to insert 2 into the list. The new node should be inserted between n...
since we need to return start//as head at the endwhile(true){//we make sure to get all cases covered and//break when we are done inserting//here we check every cur pos when we move//the cur pos can be at normal pos, where cur.next.val is bigger than ...
题目描述 题解 题解 提交记录 提交记录 代码 9 1 2 3 4 5 6 › [3,4,1] 2 [] 1 [1] 0 Source 该题目是 Plus 会员专享题 感谢使用力扣!您需要升级为 Plus 会员来解锁该题目 升级Plus 会员
1 -> 2 -> null, insert 4 at index 0, --> 4 -> 1 -> 2 -> null 1publicclassSolution {2publicListNode insert(ListNode head,intindex,intvalue) {3//Write your solution here4if(head ==null|| index < 0) {5returnhead;6}7intlength =getLength(head) ;8//corner case: index out of...
}//there is at least one node, insert the x into correct posNode cur =start;//use cur to move around , since we need to return start//as head at the endwhile(true){//we make sure to get all cases covered and//break when we are done inserting//here we check every cur pos whe...