从文件c:/test.txt读取输入流,传入scanner对象,通过next(方法)查找字符串文本,然后打印字符串文本。这样我们就成功的完成了转换。 1publicstaticvoidmain(String[] args)throwsIOException {23InputStream inputStream =newFileInputStream("c:/test.txt");4Scanner scanner =newScanner(inputStream, "UTF-8");5Str...
如果要获取输入的内容,则只需要调用Scanner的nextLine()方法即可。 Scanner也可以从字符串(Readable)、输入流、文件等等来直接构建Scanner对象,有了Scanner了,就可以逐段(根据正则分隔式)来扫描整个文本,并对扫描后的结果做想要的处理。 控制台扫描: Scannerinput=newScanner(System.in); while(true) { Stringline=sc...
如果要获取输入的内容,则只需要调用Scanner的nextLine()方法即可。 Scanner也可以从字符串(Readable)、输入流、文件等等来直接构建Scanner对象,有了Scanner了,就可以逐段(根据正则分隔式)来扫描整个文本,并对扫描后的结果做想要的处理。 控制台扫描: Scannerinput=newScanner(System.in); while(true) { Stringline=sc...
Scanner(InputStream source) 构造一个新的 Scanner,它生成的值是从指定的输入流扫描的。 Scanner(InputStream source, String charsetName) 构造一个新的 Scanner,它生成的值是从指定的输入流扫描的。java.util.jar 中InputStream 的使用java.util.jar 中InputStream 的子类 class JarInputStream JarInputStream...
Method 3: Using Scanner Java’s Scanner class can also be used to convert an InputStream to a String. We can create a new Scanner object and use itsuseDelimiter()method to specify the delimiter as"\A". This causes the Scanner to read the entire input stream until the end, resulting in...
//我的菜鸡操作 String input = scanner.nextLine(); String[] a = input.split(" "); int[] b = new int[a.length]; for(int i = 0; i < a.length; i ++){ String aString = a[i]; b[i] = Integer.parseInt(aString); }查看
Okay, so now the input someone types in will be stored in your String variable from the Java Scanner. You can use that variable to now output back the line of text. The program will just echo whatever is typed in. You should be able to output the string on your own, because you sho...
Using Scanner (JDK) Scanner s = new Scanner(inputStream).useDelimiter("\\A"); String result = s.hasNext() ? s.next() : ""; Using Stream API (Java 8). Warning: This solution converts different line breaks (like \r\n) to \n. String result = new BufferedReader(new InputStreamRea...
5. JavaInputStreamto String usingScanner UsingScannerclass is not so popular, but it works. The reason it works is becauseScanneriterates over tokens in the stream, and in this process, we can separate tokens using the “beginning of the input boundary” thus giving us only one token for ...
importjava.util.Scanner; publicclassexample { publicstaticvoidmain(String[] args) { Scanner input =newScanner(System.in); System.out.print("Input a number: "); intnumber = input.nextInt(); System.out.println(number); System.out.print("Input a Boolean value: "); ...