Now let’s see the different examples of not enough input arguments in Matlab to better understand this problem as follows. First, see how not enough input argument error occurs by using the following example as follows. function Z = add(X, Y) ...
function optimization function f = myfun(x,d)function [c,ceq] = mycon(x,a,b,e)其中第一个函数，没有输入与输出。而且 ，楼主是否知道 调用function文件，不是点击文件里的run箭头，是在comand window 里输入 函数名字。而且，函数的输入要事先写好。不然就会出现 Input argument "x" is unde...
解析 a是你自定义函数exm5_2中的自变量,在m文件中,你没有赋值,当然没有定义啊!结果一 题目 这个matlab函数为什么会出现Input argument "a" is undefined.啊function exm5_2(a) % a Define the limit of variable x . x=-a:0.02:a; for i=1:length(x) if x(i)>1 y(i)=cos(2*pi*x(i)); ...
急!matlab出现Input argument "A" is undefined.输入程序调用 function[Ax]=F_tj(A,m0)%定义函数 %模糊统计,m0划分区间个数 [n,m]=size(A);%获得矩阵的行列数 Amin=A(1,1);%A的最小值 Amax=A(1,2);%A的最大值 for(i=1:n) if(A(i,1)>A(i,2))x=A(i,2);A(i,2)=A(i,1);A(...
I'm confused though becausemin(abs(example-0.01)returns a single value (0.3233), and when I try[x,y]=0.3233, it gives me an error sayingToo many input arguments. So why would Matlab accept[x,y]=min(abs(example-0.01))but not[x,y]=0.3233? How is it yieldingy=1andt=3from the ...
在语句 V=dblquad(fun,-0.6,(-(h+0.4*tan(4.1/180*pi)./(h/tan(4.1/180*pi)+0.4)).*z+h+0.4*tan(4.1/180*pi)-0.6),0,(h/tan(4.1/180*pi)+0.4))中的z没有定义
M没有定义。调用函数rand时需要提供的参数M没有定义。看来是想产生1行M列的均匀分布的随机数组，把M给一个确定的数值就好。例如：M=5;u=rand（1，5）---运行结果：u= 0.9134 0.6324 0.0975 0.2785 0.5469
把程序保存成my.m，然后在工作窗口运行 x0=[1,1];x=fsolve('my',x0)
DeployMATLABFunction That Accepts Struct Array as Input Argument This example shows how to package a MATLAB®function that accepts a struct array as input and deploy it to an application written in C++. The workflow is supported on Windows®, Linux®, andmacOSsystems. ...
You can do this in the MATLAB command window or in a separate script (M-file). Here’s how you can call the function: % Call the function with example values pts = CreatePoints(1, 10); Step 3: Complete Example To ensure that everything works ...