Traversal till now:10 9 8and we are done with right subtree traversal of the original root 7. So, now traverse the root 7 and print that: Traversal till now:10 9 8 7 Now rest of the part is traversing the left subtree of the original root which is rooted by 1 ...
http://www.geeksforgeeks.org/inorder-tree-traversal-without-recursion/ 1 #include 2 #include 3 #include 4 #include 5 #include 6 using namespace std; 7
再次,这人思维肯定特清晰。 Reference:http://www.geeksforgeeks.org/inorder-tree-traversal-without-recursion-and-without-stack/
*/publicclassMain{publicstaticvoidmain(String[] args) throws Exception {// construct the binary tree given in questionBinaryTree bt=BinaryTree.create();// traversing binary tree on InOrder traversal without recursionSystem.out.println("printing nodes of binary tree on InOrder using iteration");...
343 25 May 2012 Ackermann’s Function: A fast-growing function that tests recursion exercise solution codepad 342 22 May 2012 Hamming Codes: Send messages over a noisy channel without error exercise solution codepad 341 18 May 2012 Formatted Numeric Output: A minimal version of C’s printf fun...
编辑:发现这个随附的c + +代码。 我很难理解树被修改后如何恢复。 魔术在于else子句,一旦右叶被修改就会被击中。 请参阅代码了解详情: /* Function to traverse binary tree without recursion and without stack */ void MorrisTraversal(struct tNode *root) { struct tNode *current,*pre; if(root == ...