题目Given a binary tree, return the inorder traversal of its nodes' values. For example: Given binary tree [1,null,2,3], return [1,3,2]. Note: Recursive solution is trivial, could you do it iter…
scanf("%c",&ans); }while(ans == 'y'); printf("Inorder traversal:the elements in the tree are"); inorder(root); printf(" Preorder traversal:the elements in the tree are"); preorder(root); printf("Postorder traversal:the elements in the tree are"); postorder(root); ...
vector<int> inorderTraversal(TreeNode *root) { // Start typing your C/C++ solution below // DO NOT write int main() function vector<int> * vec = new vector<int>(); stack<TreeNode*> my_stack; while(1) { if( root) { vec->push_back(root->val); my_stack.push(root); root =...
解法一:(迭代)将根节点压入栈,当其左子树存在时,一直将其左子树压入栈,直至左子树为空,将栈顶元素弹出,将其val值放入vector中,再将其右子树循环上述步骤,直到栈为空。 (C++) 1vector<int> inorderTraversal(TreeNode*root) {2vector<int> m={};3stack<TreeNode*>stack;4if(!root)5returnm;6TreeNode...
But in reverse inorder traversal instead of traversing the left subtree first, we traverse the right subtree first and then the left subtree. So the updated rules forreverse inorder traversalis: First, traverse the right subtree Then traverse the root ...
This is how the code for In-order Traversal looks like: Example Python: definOrderTraversal(node):ifnodeisNone:returninOrderTraversal(node.left)print(node.data,end=", ")inOrderTraversal(node.right) Run Example » TheinOrderTraversal()function keeps calling itself with the current left child...
The program creates a binary tree for breadth-first traversal.But i'm trying to use Pre-Order, In-Order, Post-Order Traversal and actually i can't do that. The output of the program is not what i expected. I think i should change the preorder, inorder or postorder functions but i ...
leetcode 94.二叉树的中序遍历(binary tree inorder traversal)C语言 leetcode 94.二叉树的中序遍历(binary tree inorder traversal)C语言 1.description 2.solution 2.1 递归 2.2 迭代 1.description https://leetcode-cn.com/problems/binary-tree-inorder-traversal/ 给定一个二叉树,返回它的中序 遍历。
{19private:20vector<int>ret;21public:22vector<int> inorderTraversal(TreeNode *root) {23//Start typing your C/C++ solution below24//DO NOT write int main() function25stack<Node>s;26s.push(Node(root,false));27ret.clear();2829while(!s.empty())30{31Node node =s.top();32if(node....
{14/**15* @param root: The root of binary tree.16* @return: Inorder in vector which contains node values.17*/18public:19vector<int> inorderTraversal(TreeNode *root) {20//write your code here21vector<int>result;22if(root ==NULL) {23returnresult;24}else{25inorderCore(root, result)...