We have given an Arithmetic Expression and we have to write a program that converts the infix to postfix using stack in C. The Expression will be given in the form of a string, where alphabetic characters i.e a-
#include<stack> #include<iostream> #include<string> usingnamespacestd; //优先级判断 charcompare(charopt,charsi) { if((opt=='+'||opt=='-')&&(si=='*'||si=='/') return'<'; elseif(opt=='#') return'<'; return'>'; }
Data Structure Stack: Infix to Postfix 1#include <iostream>2#include <vector>3#include <algorithm>4#include <queue>5#include <stack>6#include <string>7#include <fstream>8#include 9#include <set>10usingnamespacestd;1112boolisoprand(charx) {13returnx >='A'&& x <='Z'|| x >='a'&&...
using std::string; char InfixToPostfix(char infix[]); struct node{ char value; struct node *link; }; node *top; class stackAlgo{ private: int counter; public: node *pushStack(node*, char); node *popStack(node*); char copyTop(node*); ...
postfix[j++] = pop(&stack); }postfix[j] = '\0'; }int main() { char infix[MAX], postfix[MAX];printf("Enter infix expression: "); scanf("%s", infix);infixToPostfix(infix, postfix);printf("Postfix: %s\n", postfix);return 0; ...
问Infix To Postfix的输出中没有运算符和括号EN编译的代码没有错误，但我的问题是，当我输入任何中缀时...
stack_problems / infix_to_postfix.cpp infix_to_postfix.cpp4.86 KB 一键复制编辑原始数据按行查看历史 mandliya提交于10年前.Day-37: Infix to postfix converter /** * Given an infix expression, convert it to postfix. Consider usual operator precedence. ...
I have written a C++ program to convert an infix expression to postfix expression using recursion. I would like to know if it can be improved if possible. Can we improve it by not usingastack? I am using avectorvector<char>as a stack here. ...
isdigit(C))); } string inToPost(string in){ stack<char> s1; string postfix; in = '(' + in + ')'; int size = in.size(); for(int i = 0; i <size; i++) { if(isalnum(in[i])||isdigit(in[i])) { postfix= postfix + in[i]; } else if(in[i]=='('){ s1.push('(...
If it is an operator, then check if priority of current operator is greater than or less than or equal to the operator at top of the stack. If priority is greater, then push operator into operator stack. Otherwise pop two operands from operand stack, pop operator from operator stack and ...