int lens[];// 记住每个节点作为起点的最大长度 public int longestIncreasingPath(int[][] matrix) { if (matrix.length == 0) return 0; int rows = matrix.length, cols = matrix[0].length; int[] digree = new int[rows * cols];// 入度 lens = new int[rows * cols]; // 初始化邻接表...
Input: matrix = [[9,9,4],[6,6,8],[2,1,1]] Output: 4 Explanation: The longest increasing path is[1, 2, 6, 9]. Example 2: Input: matrix = [[3,4,5],[3,2,6],[2,2,1]] Output: 4 Explanation: The longest increasing path is[3, 4, 5, 6]. Moving diagonally is not ...
1.题目描述(难度Hard) Given an integer matrix, find the length of the longest increasing path. From each cell, you can either move to four directions: left, right, up or down. You may NOT move diagonally or move outside of the boundary (i.e. wrap-around is not allowed). Example : ...
publicclassSolution{publicintlongestIncreasingPath(int[][] matrix){if(matrix.length ==0)return0;int[][] dp =newint[matrix.length][matrix[0].length];intres=0;for(inti=0; i < matrix.length; i++) {for(intj=0; j < matrix[0].length; j++) {if(dp[i][j] ==0) { dp[i][j] =...
classSolution{public:intlongestIncreasingPath(vector<vector<int>>&matrix){introws=matrix.size();if(rows==0)return0;intcols=matrix[0].size();vector<int>all;intdirs[4][2]={{0,1},{0,-1},{1,0},{-1,0}};unordered_map<int,vector<pair<int,int>>>maps;for(inti=0;i<rows;i++)for...
329. Longest Increasing Path in a Matrix 矩阵中的最长递增路径,给定一个整数矩阵,找出最长递增路径的长度。对于每个单元格,你可以往上,下,左,右四个方向移动。你不能在对角线方向上移动或移动到边界外(即不允许环绕)。示例1:输入:nums=[[9,9,4],[6,6,8],[2,1,1]]
// Author: Huahua // Running time: 36 ms class Solution { public: int longestIncreasingPath(vector<vector<int>>& matrix) { if (matrix.empty()) return 0; m_ = matrix.size(); n_ = matrix[0].size(); dp_ = vector<vector<int>>(m_, vector<int>(n_, -1)); int ans = 0; fo...
def longestIncreasingPath(self, matrix: [[int]]) -> int: # 如果矩阵为空,返回 0 if not matrix or not matrix[0]: return 0 # 获取矩阵的行数和列数 row, col = len(matrix), len(matrix[0]) # 记忆化递归,记录每个位置的最大值
classSolution{public:vector<vector<int>>vis;int dir[4][2]={{0,1},{0,-1},{1,0},{-1,0}};int n,m;intlongestIncreasingPath(vector<vector<int>>&matrix){n=matrix.size();if(n==0)return0;m=matrix[0].size();vis=matrix;for(int i=0;i<n;i++){for(int j=0;j<m;j++){vis...
Longest Increasing Path in a Matrix 题目链接:https://leetcode.com/problems... dfs + 记忆化搜索,用一个二维dp记录找到的最长路径的长度,如果发现dpi != 0,证明这个点被找过,不用重复。Number of Islands和这题一个思路。 public class Solution { ...