View Solution △ ABC is right angled at A . AD is perpendicular to BC. If AB = 5 cm, BC = 13 cm and AC = 12 cm, Find the area of ABC. Also find the length of AD. View Solution Recommended Questions In triangle ABC right angle at C if AC=5 cm and BC= 12 cm then area ...
Step by step video & image solution for In a right triangle ABC, right angled at C in which AB = 13cm, BC = 5cm, determine the value of cos^2 B + sin^2 A . by Maths experts to help you in doubts & scoring excellent marks in Class 10 exams.Updated on:21/07/2023 ...
5A0B CxM x In the diagram, triangle AB C is right-angled at C and M is the mid-point of BC. It is given that angleABC=1/3πr adians and angle BAM = 0 radians. Denoting the lengths of BM and M C by x,(i) find AM in terms of x,[3] (i) showthatθ=1/6π-tan^(-...
right-angled triangle meaning, definition, what is right-angled triangle: a triangle which has an angle of 90°: Learn more.
百度试题 结果1 题目 In a right-angled triangle with an angle of 60°, the ratio of the length of the opposite side of the angle of 60° to the length of the hypotenuse is 相关知识点: 试题来源: 解析 反馈 收藏
In the right triangle ABC having C= 90 degrees, b = x and c = 5x, find sin A, cos A, tan A, and sin B, cos B, tan B.Trigonometric FunctionsIn mathematics, trigonometric functions are basically defined in right-angled triangles as the rel...
One of the angles of a right-an gled triangle is15∘and the hy- potenuse is 1 metre. The area of the triangle (in square cm.) is View Solution In a right triangle ABC, right angled at C, if a = 7 cm and b =7√3cm, then∠A= ...
Example: 2A In the given right angled triangle ABC, ∠ B = 90°, BD⊥AC ,A B = 5, BC =12. Find the value of sin 0, cos Θ and tan 0.D50B C12 相关知识点: 试题来源: 解析 In right angled triangle Now,In , taking as the angle of reference, then, ...
Answer Step by step video & image solution for In a triangle A B C , right angled at B , then r=(A B+B C-A C)/2 b. r=(A B+A C-B C)/2 c. r=(A B+B C+A C)/2 d. R=(s-r)/2 by Maths experts to help you in doubts & scoring excellent marks in Class 11 exam...
1 In a right-angled triangle ABC, ∠ABC = 90°, D is a point on AB, E F is the perpendicular bisector of AD, intersecting AC at E with F being the foot of the Aperpendicular, and the extension of E D intersects the extension of CB at point G.F EProve: EG = EC.D G B ...