1物理电容电压计算Inthecircuitshowninthefigure, allthecapacitorsareair-filled. WiththeswitchSopen, the 40.0-µFcapacitorhasaninitialchargeof 5.00 µCwhiletheotherthreecapacitorsareuncharged. Theswitchisthenclosedandleftclosedforalongtime. Calculatetheinitialandfinalvaluesofthetotalelectricalenergystoredinthese...
百度试题 题目 In the circuit shown in the following Figure .When the resistance R2 increases, the current I will( ). A.increaseB.decreaseC.remain the sameD.not sure 相关知识点: 试题来源: 解析 A 反馈 收藏
The diode used in the circuit shown in the figure has a constant voltage drop of 0.5 V at all currents and a maximum power rating of 100 mW. What should be the value of the resistor R, connected in series with the diode for obtaining maximum current is
A. 正确 B. 错误 查看完整题目与答案 【单选题】The circuit is shown in the figure,which voltage transfer characteristic is right( ). A. B. C. D. 查看完整题目与答案 参考解析: A;B;C AI解析 重新生成最新题目 【单选题】如果将人眼比作照相机的话,则相当于暗盒的是( )。 查看完整...
计算过程：电容两端电压=Q/C=5.00 µC/40µF=0.125（伏特）初始时候的静电能=QU/2=5.00 µC×0.125V/2=3.125×10^-7（库伦·伏特）开关闭合很久后，电路等效如下图：总电路等效为一个60µF的电容，原先在C1上的5.00 µC的电荷会分散到各个电容上（C1、C2...
题目出得不是很好。 非常相 讲师 8 电路的暂态与稳态!第一题说的是,电容没有电,开关闭合后的过程:总电流经R1后,分两路,一路静R2,一路经C(充电电流),所以流经R1的电流比流经R2的电流大!第二题说的是,开关并和很久了,电路稳定了,这是电容充满,没有充电电流,所以R1 、R2的电流相等! Aavivachc 小...
The circuit shown in the figure is a图中所示的电路是一个【图片】A.one-shot. 单稳。B.multivibrator. 多谐振
百度试题 题目In the circuit shown in the following Figure .I=( ). A.6AB.4AC.2AD.-2A相关知识点: 试题来源: 解析反馈 收藏
For the circuit shown in Figure, the feedback path T2-Rf1-T1 is ( ) A、DC positive feedback B、ac positive feedback C、ac negative feedback D、DC negative feedback 点击查看答案
Net emf of the circuit =E1-E2=6V Total resistance of the circuit =R+r1+r2=4Omega :. Current in the circuit i=("netemf")/("total resistance") = 6/4 = 1.5A Now, V1=E1-ir1=10-(1.5)(1) =8.5V V2=E2+ir2=4+(1.5)(1) =5.5V