we need to go through all its nodes in some order, which can be — inorder, preorder, or postorder depth-first traversal and level order, breadth-first traversal, or some hybrid scheme. In this article, we discuss inorder tree traversal without the use of recursion or stack...
publicList<Integer>inorderTraversal3(TreeNoderoot){List<Integer>ans=newArrayList<>();TreeNodecur=root;while(cur!=null){//情况 1if(cur.left==null){ans.add(cur.val);cur=cur.right;}else{//找左子树最右边的节点TreeNodepre=cur.left;while(pre.right!=null&&pre.right!=cur){pre=pre.right;}...
65publicstaticvoidinOrder(TreeNode root){66if(root ==null)return;67inOrder(root.left);68visit(root);69inOrder(root.right);70}7172publicstaticvoidinOrder2(TreeNode root){73if(root ==null)return;74Stack<TreeNode> stack =newStack<TreeNode>();75while(!stack.empty() || root !=null){76...
子树递归同理 中序Inorder: 先访问左子树,然后访问根节点,最后访问右子树. 后序Postorder:先访问左子树,然后访问右子树,最后访问根节点. classNode:def__init__(self,key):self.left=Noneself.right=Noneself.val=keydefprintInorder(root):ifroot:printInorder(root.left)print(root.val)printInorder(root.r...
总结下: 首先发明这个算法的人肯定是对那个什么Threaded Binary Tree烂熟于心啊;其次,对inorder遍历也是理解透彻啊。。。 再次,这人思维肯定特清晰。 Reference:http://www.geeksforgeeks.org/inorder-tree-traversal-without-recursion-and-without-stack/
*/classSolution{public List<Integer>preorderTraversal(TreeNode root){List<Integer>result=newLinkedList<>();TreeNode current=root;TreeNode prev=null;while(current!=null){if(current.left==null){result.add(current.val);current=current.right;}else{// has left, then find the rightmost of left su...
* TreeNode(int x) { val = x; } * } */publicclassSolution{public List<Integer>inorderTraversal(TreeNode root){ArrayList<Integer>result=newArrayList<Integer>();if(root==null)returnresult;inorderTraversal(root,result);returnresult;}privatevoidinorderTraversal(TreeNode root,ArrayList<Integer>result...
* TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: /*递归版 vector<int> inorderTraversal(TreeNode *root) { vector<int> res; solve(root,res); return res; } void solve(TreeNode *root,vector<int> &res) ...
Given preorder and inorder traversal of a tree, construct the binary tree. Note: You may assume that duplicates do not exist in the tree. 1 /** 2 * Definition for binary tree 3 * struct TreeNode { 4 * int val; 5 * TreeNode *left; ...
Binary search tree traversal in order, postorder, and preorder traversal. Top of the tree, the height of the tree inorder-traversalpreorder-traversalpostorder-traversaltop-view-binary-treeheight-of-tree UpdatedSep 2, 2020 Python jaydattpatel/Binary-Tree ...