Given the root of a binary tree, return the inorder traversal of its nodes' values. Example 1: Input: root = [1,null,2,3] Output: [1,3,2] Example 2: Input: root = [] Output: [] Example 3: Input: root = [1] Output: [1] Constraints: The number of nodes in the tree is...
binary-tree-inorder-traversal /** * * @author gentleKay * Given a binary tree, return the inorder traversal of its nodes' values. * For example: * Given binary tree{1,#,2,3}, 1 \ 2 / 3 * return[1,3,2]. * Note: Recursive solution is trivial, could you do it iteratively?
Given a binary tree, return theinordertraversal of its nodes' values. For example: Given binary tree{1,#,2,3}, 1 \ 2 / 3 return[1,3,2]. 1/**2* Definition for binary tree3* struct TreeNode {4* int val;5* TreeNode *left;6* TreeNode *right;7* TreeNode(int x) : val(x)...
* TreeNode right; * TreeNode(int x) { val = x; } * } */ class Solution { public List<Integer> inorderTraversal(TreeNode root) { List<Integer> result = new LinkedList<Integer>(); if (root != null) { in_order(result, root.left); result.add(root.val); in_order(result, root....
94. Binary Tree Inorder Traversal 题目描述 Given a binary tree, return theinorder For example: Given binary tree [1,null,2,3], 1 \ 2 / 3 return [1,3,2]. Note: 思路 本题的目的是将一个二叉树结构进行中序遍历输出...
public List<Integer> inorderTraversal(TreeNode root) { List<Integer> ans = new ArrayList<>(); getAns(root, ans); return ans; } private void getAns(TreeNode node, List<Integer> ans) { if (node == null) { return; } getAns(node.left, ans); ans.add(node.val); getAns(node.right...
Binary Trees Preorder Traversal of a tree both using recursion and Iteration <-> Binary Trees Postorder Traversal of a tree both using recursion and Iteration <-> Binary Trees Left View of a tree <-> Binary Trees Right View of Tree https://leetcode.com/problems/binary-tree-right-side-view...
Same Tree -https://leetcode.com/problems/same-tree/ Invert/Flip Binary Tree -https://leetcode.com/problems/invert-binary-tree/ Binary Tree Maximum Path Sum -https://leetcode.com/problems/binary-tree-maximum-path-sum/ Binary Tree Level Order Traversal -https://leetcode.com/problems/binary-...
* TreeNode right; * TreeNode(int x) { val = x; } * } */classSolution{public List<Integer>preorderTraversal(TreeNode root){List<Integer>result=newLinkedList<>();TreeNode current=root;TreeNode prev=null;while(current!=null){if(current.left==null){result.add(current.val);current=current...
you'll often need some way to get access to each object in the collection. In fact, depending on the collection, you may want several ways to access each object such as front to back, back to front, preorder or postorder. To keep the collection simple, the traversal code itself is oft...