LC.232. Implement Queue using Stacks(use two stacks) https://leetcode.com/problems/implement-queue-using-stacks/description/ Implement the following operations of a queue using stacks. push(x) -- Push element x to the back of queue. pop() -- Removes the element from in front of queue. ...
"40. Implement Queue by Two Stacks" / "225. Implement Stack using Queues" 本题难度: Medium/Easy Topic: Data Structure stack/queue Desc
Initialize your data structure here. """#why use two stack hereself.s1=[]self.s2=[]defpush(self,x):""" Push element x to the back of queue. :type x: int :rtype: None """#把s1中的内容挨个pop出去,每pop一个向s2中append一个#s1为空之后将新加进来的元素放到stack的最底部#再重复第...
this question inspect the difference between Queue and Stack. They have different way to deal with input data and will see different output. In my solution, I use two stacks. One stores all data, this other one is used for operate pop() and peek(); here makes stack different. following ...
Leetcode 232 Implement Queue using Stacks 和 231 Power of Two,1.232ImplementQueueusingStacks1.1问题描写叙述使用栈模拟实现队列。模拟实现例如以下操作:push(x).将元素x放入队尾。pop().移除队首元素。peek().获取队首元素。empty().推断队列是否为空。注意:仅仅能
Leetcode Implement Queue using Stacks Implement the following operations of a queue using stacks. push(x) -- Push element x to the back of queue. pop() -- Removes the element from in front of queue. peek() -- Get the front element....
In which case, we'll have to use a circular array or implement two stacks in the given array and then implement a queue using the two stacks.
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2. queue(先进先出) : poll = remove 拿出并返第一个值; element = peek 返第一个值; add = offer 加入新值在后面并返回true/false。 做此题时, 第一个stack为基础, 第二个stack为媒介来颠倒顺序, 加时从第一个加, 取时从第二个取。
packageleetcodetypeMyStackstruct{enque[]intdeque[]int}/** Initialize your data structure here. */funcConstructor225()MyStack{returnMyStack{[]int{},[]int{}}}/** Push element x onto stack. */func(this*MyStack)Push(xint){this.enque=append(this.enque,x)}/** Removes the element on top...