## LeetCode 232## Impletement Queue using StackclassMyQueue:def__init__(self):self.l1=[]## stack 1 = l1self.l2=[]## stack 2 = l2defpush(self,x:int)->None:## Push x onto queueself.l1.append(x)## The right of the list = the top of the stack = the back of the queuedef...
LeetCode 232. Implement Queue using Stacks (用栈实现队列) 题目 链接 https://leetcode-cn.com/problems/implement-queue-using-stacks/ 问题描述 请你仅使用两个栈实现先入先出队列。队列应当支持一般队列支持的所有操作(push、pop、peek、empty): 实现MyQueue 类: void push(int x) 将元素 x 推到队列的...
}/** Removes the element from in front of queue and returns that element. */publicintpop(){if(empty()) {thrownewIllegalArgumentException("[ERROR] The queue is empty!"); }if(outStack.isEmpty()) {while(!inStack.isEmpty()) { outStack.push(inStack.pop()); } }returnoutStack.pop()...
MyQueue object will be instantiated and called as such:* obj := Constructor();* obj.Push(x);* param_2 := obj.Pop();* param_3 := obj.Peek();* param_4 := obj.Empty();*/ 题目链接: Implement Queue using Stacks : https://leetcode.com/problems/implement-queue-using-stacks/ 用栈...
queue.empty(); // returns false 1. 2. 3. 4. 5. 6. 7. 思路是需要用到两个栈,用first和second表示。以下分别解释一下每个函数的实现方式。 push() - 将元素加入队列。这没什么可说的,加入到第一个栈first中。时间O(1) pop() - 弹出队列的首个元素。因为stack只会弹出最后一个放入的元素,所以只...
1. class MyQueue { 2. new Stack<Integer>(); 3. new Stack<Integer>(); 4. 5. // Push element x to the back of queue. 6. public void push(int x) { 7. while (!pop.isEmpty()) { 8. push.push(pop.pop()); 9. }
classMyQueue{privateStack<Integer>stack;/** Initialize your data structure here. */publicMyQueue(){stack=newStack<Integer>();}/** Push element x to the back of queue. */publicvoidpush(intx){stack.push(x);}/** Removes the element from in front of queue and returns that element. */...
Implement the following operations of a queue using stacks. push(x) -- Push element x to the back of queue. pop() -- Removes the element from in front of queue. peek() -- Get the front element. empty() -- Return whether the queue is empty. ...
[]self.outstack = []def push(self, x):"""Push element x to the back of queue.:type x: int:rtype: void"""# 插入队列时,我们将值放入instack栈顶self.instack.append(x)def pop(self):"""Removes the element from in front of queue and returns that element.:rtype: int"""# 需要...
You may assume that all operations are valid (for example, no pop or top operations will be called on an empty stack). 解题思路: 方法一(两个队列): 队列先进后出,栈后进先出。 用队列实现栈,可以用两个队列完成题解: 出栈:入栈时用 queue1 来存入节点;出栈时queue1 内节点顺序出队列并入队列到...