If two vectors are perpendicular, their dot product is zero and their cross product has the maximum magnitude. () A. 正确 B. 错误 如何将EXCEL生成题库手机刷题 如何制作自己的在线小题库 > 手机使用 分享 反馈 收藏 举报 参考答案: A 复制 纠错 举一反三 储油柜的采用增大了变压器油与空气...
16If there are two vectors,AB and CD which do not coincide with each other,and 2 AB3 CD,then the relationship between the positions of segments AB and CD is ,and the relationship between the lengths of segments AB and CD is6 If there are two vectors, ABandCD which do not coincide wi...
Test if two vectors contains the same elements independently of their orderMarc Girondot
A. Increases by 30 degrees B. Decreases by 30 degrees C. Remains the same D. Cannot be determined 相关知识点: 试题来源: 解析 A。本题考查向量角度的变化。一个向量逆时针旋转 30 度,两向量之间的夹角会增加 30 度。反馈 收藏
百度试题 结果1 题目Ifand be two perpendicuar vectors. then A) ii-i_1=u_1=-6) |a-b|=4i+b-|i| c |i(i)i]=(i+i)DI All of these 相关知识点: 试题来源: 解析 D 反馈 收藏
Two vectors u and v are given as u = 5i - 9j - 9k and v = 45i + 43j - k. How do you find their dot product? Let v1 = (1, 0, 1) and v2 = (0, 2, 1). What is the dot product of V1 and v2? What is the cross produc...
If x and y are two distincts vectors in , and Ax=Ay, then det(A)=0.A.正确B.错误的答案是什么.用刷刷题APP,拍照搜索答疑.刷刷题(shuashuati.com)是专业的大学职业搜题找答案,刷题练习的工具.一键将文档转化为在线题库手机刷题,以提高学习效率,是学习的生产力工具
Let @ and b be two unit vectors such that the angle between them iSπ/(4) . If 0 is the angle between the vectors (@ + b) and (@ + 2b+ 2(@ × b)), then the value of 164 cos2 0 is equal to :Correct Answer A 90+27√2 B 45+18√2 c 90+3√2 D 54+90√2 ...
Step by step video & image solution for If vec a\ a n d\ vec b are two vectors such that | vec axx vec b|=3\ a n d\ vec adot vec b=1, find the angle between vec a\ a n d\ vec b . by Maths experts to help you in doubts & scoring excellent marks in Class 12 exams...
To find the angle between two vectors →a and →b given the condition |→a×→b|=→a⋅→b, we can follow these steps:1. Understand the given condition: We have the condition that the magnitude of the cross product of vectors →a and →b is equal to the dot product of the same...