If sin x + sin y = a and cos x + cos y = b, than tan2(x+y2)+tan2(x−y2) is equal to: AA) a^4+b^4+4b^2)/(a^2b^2+b^2) BB) (a^4-b^4+4b^2)/(a^2b^2+b^4) CC) (a^4-b^4+4a^2)/(a^2b^2+a^4) DD) None of theseSubmit ...
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If y=sinh−1 1, then sinh y = 1. Hence use the definition of sinh y to find sinh−1 1 as a natural logarithm. Hyperbolic Functions: The word hyperbolic comes from the hyperbola section. So, we can say that the hyperbolic function can be ...
b. {eq}\sin^{-1} (-2) {/eq}. Arcsine - Definition The "inverse sine function" is also referred to as "arcsine function" whereas it uses the trigonometric sine ratio as an input to the function and gives an output in the form of an acute angle of a right triangle....
The inverse function is also called anti-function and it is the opposite of the main function. g(x) g−1(x) f(x)h(x) f(x),h(x) Answer and Explanation:1 ANSWER:(b)x1−x Explanation: We are giveng(x)=x1+x Sincey=g(...
4.2 Block diagram with controller parameterized for control objective Plant Output It is instructive here to note the following: if the behavior of the plant can be viewed as a mathematical function, then this problem can be solved by a controller that is the inverse of the plant function. Of...
IFAS systems are inherently complex due to the hybrid use of both suspended and attached bacterial colonies for the purpose of pollutant degradation as part of wastewater treatment. This poses challenges when attempting to represent these systems mathema
This implies that the average value of the (inverse) dilaton scales as gs−1 ∼ VC1/Y2 ∼ eˆ3/4 . (2.9) Finally, the AdS4 radius RAdS scales like RAdSMP ∼ eˆ9/4 . (2.10) Therefore the 4d EFT considered in [11] suggests that as we increase eˆ along the ...
State whether the following statement is true or false. \int_0^\pi f(x) \cos x dx = - \int_0^\pi f'(x) \sin x dx Determine whether the statement is true or false given that f(x) = ln x, where x ...
tan^(-1) ((1 -x^(2))/(2x)) + cos^(-1) ((1 -x^(2))/(1 + x^(2))) = (pi)/(2) - tan^(-1) ((2x)/(1 - x^(2))) + cos^(-1) ((1 -x^(2))/(1 + x^(2))) = (pi)/(2) - 2tan^(-1) x + 2tan^(-1) x " " ("as " x in (0, 1)) = (...