解:(1)由题f'(x)=3x2-6x+3a,故f'(①)=3a-3。又f(1)=1,所以所求的切线方程为y=(3a-3)x-3a+4;(2)f'(x)=3(x-1)2+3(a-1)(0≤x≤2),故1a≤0时,f(x)≤0,f(x)在[0,2]单减,故1f(x)lmx=max{1f(0)1,f(2)川}=3-3a;2 21-|||-a时,f(x)20,f(x)在[0,...
百度试题 结果1 题目【题目】If x3+ax2+br+8 has two factors, x+1 and x+2,a+b=如果 x^3+ax^2+bx+8 有两个因式x+1和x+2,则a+b= 相关知识点: 试题来源: 解析 【解析】 21;21
4、ve integer that has exactly two different positive divisors,1 and itself.* A composite number is a positive integer greater than 1 that has more than two divisors.* The numbers 1 is neither prime nor composite, 2 is the only even primenumber.4. factor(divisor) & prime factor 因子和质...
If the product of a simple binomial x+m and a quadratic (x-1)2 is a cubic multinomial
利用三角不等式得到所求.[详解]解:因为函数f(x)=x3+ax+b定义域为[-1,2],记If(x)的最大值为M,所以|f(1)|,|f(2)|,|f(1)|都不大于M,即M≥f(-1)|=|-1-a+b,M≥f(1)=|1+a+b,M≥f(2)=|8+2a+b,所以M+3M+2M≥|-1-a+b+3+3a+3b+|16+4a+2b≥≥|(-1-a+b)+(...
解答:解:(x+m)(x-1)2=(x+m)(x2-2x+1)=x3-(2-m)x2+(1-2m)x+m=x3+ax+b, 可得2-m=0,1-2m=a,m=b, 解得:a=-3,b=2,m=2. 故答案为:-3,2,2. 点评:此题考查了多项式乘以多项式,熟练掌握运算法则是解本题的关键. 练习册系列答案 ...
This is a modal window. The media could not be loaded, either because the server or network failed or because the format is not supported. 打开App查看高清大图杰冠乒乓球培训 9月24日 16:49 关注 经过一个暑假的沉淀,小朋友进步不少呀 一起来学乒乓球#乒乓球训练 杰冠乒乓球馆培训俱乐部 浦东新...
+ PUSH AX + MOV AX,[BX][SI] + SUB AX,X[DI] + CMP AX,0 + JGE ??0000 + NEG AX + ??0000:MOV CX,AX + POP AX 该调用有效 (3) + PUSH AX + MOV AX,[BX][SI] + SUB AX,X[BX][SI] + CMP AX,0 + JGE ??0000 + NEG AX + ??0000:MOV 240H,AX + POP AX 该调用无...
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.已知函数f(x)=x3+ax+14,g(x)=lnx.记函数h(x)=f(z)+g(x2+If(z)-g(z)l2,若h(x)在(0,+∞)上恰有2个不同的零点,则实数